使用While和grep组合 - "意外标记'<'附近的语法错误"

Question

我试图将grep的stdout指向while循环中的read命令的stdin

下面的代码给我语法错误 - "语法错误附近意外令牌`<'"

while read -r line ; do
 echo "Processing $line "
 IFS=: read var1 var2 var3 <<< $line
 if [ -n "$(expr match "$var3" '.*\(BEGIN\).*')" ]; then
   echo "Found BEGIN"
   (( var2 += 1 ))
   read -r line1
   IFS=: read var4 var5 var6 <<< $line1
   if [ -n "$(expr match "$var6" '.*\(END\).*')" ]; then
     echo "Found END"
     (( var5 -= 1 ))
     sed -i -e "$var2,$var5 s/# //" -e "$var2,$var5 s%/\* %%" -e "$var2,$var5 s% \*/%%" $var1
   fi
 else
   echo "Found NOTHING"
   sed -i -e "$var2 s%// %%" $var1
 fi
done < <(grep -H -r -n Uncomment *)

Answer 1

该< <(...)语法仅在炮弹可用ksh扩展,像ksh本身或bash.当我运行你的代码时,sh我得到了完全相同的错误.

更新(或添加!)你的shebang是#!/bin/ksh或#!/bin/bash