Sha*_*ngh 1 java httpurlconnection
我试图发布参数并从输入流读取重定向的页面,但我不知道任何此异常
Exception in thread "main" java.lang.IllegalStateException: Already connected
at java.net.URLConnection.setDoOutput(URLConnection.java:900)
at sun.net.www.protocol.https.HttpsURLConnectionImpl.setDoOutput(HttpsURLConnectionImpl.java:455)
at com.company.Main.main(Main.java:58)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:483)
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:144)
Run Code Online (Sandbox Code Playgroud)
码:
try {
CookieHandler cookieHandler = null;
CookieManager.setDefault(cookieHandler);
HttpURLConnection urlConnection = (HttpURLConnection) new URL("site").openConnection();
InputStream i = new BufferedInputStream(urlConnection.getInputStream());
StringBuilder stringBuilder =new StringBuilder();
int c;
while ((c=i.read())!=-1){
stringBuilder.append((char)c);
}
// for getting the post paramters that is user name and password field
Pattern p = Pattern.compile("<input name=\"\\w{22}\" type=\"text\" id=\"\\w{22}\" />");
Matcher matcher = p.matcher(stringBuilder.toString());
String user_name = null;
while (matcher.find()){
user_name = matcher.group().split("\"")[1];
}
String password = null;
p= Pattern.compile("<input name=\"\\w{22}\" type=\"password\" id=\"\\w{22}\" />");
matcher= p.matcher(stringBuilder.toString());
while (matcher.find()){
password = matcher.group().split("\"")[1];
}
System.out.print(user_name + " " + password);
String urlParameters = user_name+"=xyz&"+password+"=xyz";
byte[] postData = urlParameters.getBytes( StandardCharsets.UTF_8 );
int postDataLength = postData.length;
urlConnection.setDoOutput(true);
urlConnection.setDoInput(true);
urlConnection.setRequestMethod("POST");
urlConnection.setRequestMethod(Integer.toString(postDataLength));
Writer writer = new BufferedWriter(new OutputStreamWriter(urlConnection.getOutputStream()));
writer.write(urlParameters);
writer.flush();
urlConnection.setDoInput(true);
urlConnection.getContent();
while ((c=i.read())!=-1){
System.out.print((char)c);
}
} catch (IOException e) {
e.printStackTrace();
}
Run Code Online (Sandbox Code Playgroud)
你需要调用urlConnection.setDoInput(true),urlConnection.setDoOutput(true),urlConnection.setRequestMethod("POST"),urlConnection.setRequestMethod(Integer.toString(postDataLength))和之前调用更改查询任何其他方法urlConnection.getInputStream(),并urlConnection.getOutputStream()为这些方法实际上将启动请求,以便调用一次实在来不及修改,这就是为什么你这样做的原因请求Exception.
响应更新
您实际面临的主要问题是由于您希望重用HttpURLConnection它而不打算重用,这就是您遇到此异常的原因,您需要HttpURLConnection为每个HTTP请求创建一个新的.
| 归档时间: |
|
| 查看次数: |
3078 次 |
| 最近记录: |