Cue*_*Cue 3 string xcode rot13 swift
我想创建一个接收String并返回一个String的函数,并在字母表中用字母后面的字母替换一个字母13个字母(ROT13).我发现了很多例子,遗憾的是由于各种错误,我无法让它工作.例如这一个:
var key = [String:String]() // EDITED
let uppercase = Array(arrayLiteral: "ABCDEFGHIJKLMNOPQRSTUVWXYZ")
let lowercase = Array(arrayLiteral: "abcdefghijklmnopqrstuvwxyz")
for i in 0 ..< 26 {
key[uppercase[i]] = uppercase[(i + 13) % 26]
key[lowercase[i]] = lowercase[(i + 13) % 26]
}
func rot13(s: String) -> String {
return String(map(s, { key[$0] ?? $0 }))
}
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实际上你最初的映射方法Character很好:
var key = [Character: Character]()
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但是这两个数组必须是以下数组Characters:
let uppercase = Array("ABCDEFGHIJKLMNOPQRSTUVWXYZ".characters)
let lowercase = Array("abcdefghijklmnopqrstuvwxyz".characters)
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(备注:您(几乎)从不想xxxLiteral:明确地调用初始化程序.这样做(几乎)总是隐藏实际问题.)
现在你填写字典的代码有效:
for i in 0 ..< 26 {
key[uppercase[i]] = uppercase[(i + 13) % 26]
key[lowercase[i]] = lowercase[(i + 13) % 26]
}
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转换字符串可以完成
// map
// String --> Characters ---> Characters -> String
func rot13(s: String) -> String {
return String(s.characters.map { key[$0] ?? $0 })
}
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这是另一种不使用查找数组的方法:
let input = "Hello World"
func rot13(unicodeScalar: UnicodeScalar) -> UnicodeScalar {
var result = unicodeScalar.value
if 65...90 ~= result { //Detect capital A ... Z
result = (result + 13 - 65) % 26 + 65
}
else if 97 ... 122 ~= result { //Detect lowercase a ... z
result = (result + 13 - 97) % 26 + 97
}
return UnicodeScalar(result)
}
func rot13(_ input: String) -> String {
let resultUSs = input.unicodeScalars.map(rot13)
var resultUSV = String.UnicodeScalarView()
resultUSV.appendContentsOf(resultUSs) //for Swift 2.2
//resultUSV.append(contentsOf: resultUSs) //for Swift 3.0
return String(resultUSV)
}
let output = rot13(input)
print(output)
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这是@AMomchilov 的替代版本,rot13它使用 aswitch和 less 数学并消除幻数:
func rot13(_ unicodeScalar: UnicodeScalar) -> Character {
var result = unicodeScalar.value
switch unicodeScalar {
case "A"..."M", "a"..."m":
result += 13
case "N"..."Z", "n"..."z":
result -= 13
default:
break
}
return Character(UnicodeScalar(result)!)
}
func rot13(_ input: String) -> String {
return String(input.unicodeScalars.map(rot13))
}
print(rot13("Uryyb, jbeyq!")) // "Hello, world!"
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泛化到 rotN
我已经采用了rot13上面的函数,并rotN通过让它们采用ClosedRange<UnicodeScalar>. 这可以让你实现rot13,rot47,rot5,和的组合rot13,并rot5在一个非常直接的方式。
func rotN(_ unicodeScalar: UnicodeScalar, intervals:[ClosedRange<UnicodeScalar>]) -> Character {
var result = unicodeScalar.value
for interval in intervals {
let half = (interval.upperBound.value - interval.lowerBound.value + 1) / 2
let halfway = UnicodeScalar(interval.lowerBound.value + half)!
switch unicodeScalar {
case interval.lowerBound..<halfway:
result += half
case halfway...interval.upperBound:
result -= half
default:
break
}
}
return Character(UnicodeScalar(result)!)
}
func rotN(_ input: String, intervals:[ClosedRange<UnicodeScalar>]) -> String {
return String(input.unicodeScalars.map {rotN($0, intervals: intervals)})
}
func rot13(_ input: String) -> String {
return rotN(input, intervals:["A"..."Z", "a"..."z"])
}
func rot47(_ input: String) -> String {
return rotN(input, intervals:["!"..."~"])
}
func rot5(_ input: String) -> String {
return rotN(input, intervals:["0"..."9"])
}
func rot13and5(_ input: String) -> String {
return rotN(input, intervals:["A"..."Z", "a"..."z", "0"..."9"])
}
print(rot13("Uryyb, jbeyq!")) // "Hello, world!"
print(rot47("%96 BF:4< 3C@H? 7@I")) // "The quick brown fox"
print(rot5("6 + 7 = 8")) // "1 + 2 = 3"
print(rot13and5("Whyl 9, 6221")) // "July 4, 1776"
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这是rotN基于@AMomchilov's原始版本的一个版本rot13:
func rotN(_ unicodeScalar: UnicodeScalar, intervals:[ClosedRange<UnicodeScalar>]) -> UnicodeScalar {
var result = unicodeScalar.value
for interval in intervals {
let start = interval.lowerBound.value
let length = interval.upperBound.value - start + 1
if interval ~= unicodeScalar {
result = (result + length/2 - start) % length + start
}
}
return UnicodeScalar(result)!
}
func rotN(_ input: String, intervals:[ClosedRange<UnicodeScalar>]) -> String {
return String(input.unicodeScalars.map {Character(rotN($0, intervals:intervals))})
}
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