杰克逊日期格式问题:java bean到JSON字符串转换

Question

我正在使用Jackson 2.7.4版本将java bean转换为JSON字符串.这样做,我面临着日期格式问题.正在使用Java 1.7版本.

豆 :

public class BaseBean {

    private java.util.Date fromDate;

    public Date getFromDate() {
        return fromDate;
    }

    public void setFromDate(Date fromDate) {
        this.fromDate = fromDate;
    }
}

我的日期格式低于日期

{"fromDate":1465370289436}

这不是我要求的.然后我配置下面的代码

ObjectMapper objectMapper = new ObjectMapper();
objectMapper.configure(com.fasterxml.jackson.databind.SerializationFeature.WRITE_DATES_AS_TIMESTAMPS , false);
jsonInString = objectMapper.writeValueAsString(objJava);

然后我在JSON中获得以下日期格式:

{"fromDate":"2016-06-08T07:47:06.636+0000"}

预计日期格式:

{"fromDate":{"date":8,"day":3,"hours":12,"minutes":48,"month":5,"seconds":9,"time":1465370289436,"timezoneOffset":-330,"year":116}}

是否有任何配置来处理它并在JSON字符串中获得预期的日期格式.

Answer 1

JSON 日期序列化程序：

public class CustomDateSerializer extends JsonSerializer<Date> {

@Override
public void serialize(Date date, JsonGenerator jgen, SerializerProvider provider) throws IOException,
        JsonProcessingException {

    // below methods of Date object is deprecated - consider this as sample example 
    int idate = date.getDate();
    int day = date.getDay();
    int hours = date.getHours();
    int minutes = date.getMinutes();
    int month = date.getMonth();
    int seconds = date.getSeconds();
    long time = date.getTime();
    int timezoneOffset = date.getTimezoneOffset();
    int year = date.getYear();

    jgen.writeStartObject();

    jgen.writeNumberField("date", idate);
    jgen.writeNumberField("day", day);
    jgen.writeNumberField("hours", hours);
    jgen.writeNumberField("minutes", minutes);
    jgen.writeNumberField("month", month);
    jgen.writeNumberField("seconds", seconds);
    jgen.writeNumberField("time", time);
    jgen.writeNumberField("timezoneOffset", timezoneOffset);
    jgen.writeNumberField("year", year);

    jgen.writeEndObject();      
}

@Override
public Class<Date> handledType() {
    return Date.class;
}

}

在 SimpleModule 中设置序列化器：

ObjectMapper objectMapper = new ObjectMapper();
    String jsonInString = "";
    try {
        SimpleModule myModule = new SimpleModule();

        myModule.addSerializer(Date.class, new CustomDateSerializer());
        objectMapper.registerModule(myModule);
        jsonInString = objectMapper.writerWithDefaultPrettyPrinter().writeValueAsString(objJava);
    } catch (JsonProcessingException e1) {          
        e1.printStackTrace();
    }

希望这会有所帮助！