我有以下数据:
Newspaper Month Year Date Topic1 Topic2 Topic3 Topic4 Topic5
1 Scotsman December 2005 December 2005 0.013749700 0.000127470 0.38575261 0.000127470 0.070778523
2 Scotsman December 2005 December 2005 0.000165017 0.000165017 0.05219433 0.004611941 0.000165017
3 Scotsman December 2005 December 2005 0.000356507 0.024344932 0.01135670 0.000356507 0.000356507
4 Scotsman December 2005 December 2005 0.000185186 0.000185186 0.10796924 0.044639345 0.106613401
5 Scotsman December 2005 December 2005 0.065869506 0.009775978 0.09610254 0.017584819 0.000103681
6 Scotsman December 2005 December 2005 0.000153257 0.000153257 0.11443001 0.000153257 0.046316677
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我想创建一个单独的变量,对应于TopicN更高的百分比.
在第一篇文章(行)的情况下,它将是3.任何想法?
您可以max.col()在主题列上使用.如果df是数据,请尝试
max.col(df[grepl("^Topic", names(df))])
# [1] 3 3 2 3 3 3
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所以要添加一个新列MaxPct,我们可以做到
df$MaxPct <- max.col(df[grepl("^Topic", names(df))])
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