jam*_*ind 9 c# simple-injector serilog
Serilog允许创建一个上下文感知记录器:
Log.ForContext<T>()
我想用SimpleInjector注册Serilog,这T是消费者的类型,即它注入的是哪个类.
例如
public class Car
{
public Car(ILogger logger) <= would be injected using Log.ForContext<Car>()
{
}
}
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我可以看到这已经完成了AutoFac.
通过SimpleInjector文档,有一个非常有希望的重载RegisterConditional()(使用Func<TypeFactoryContext, Type>参数).
c.RegisterConditional(typeof (ILogger),
x => Log.ForContext(x.Consumer.ImplementationType), <= won't compile as expecting a Type
Lifestyle.Scoped,
x => true);
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但是,我不想告诉SimpleInjector 要构建哪个 Type,而是如何构建一个.
jan*_*ann 10
我已经将Serilog与Simple Injector集成在一起,其代码基于StackOverflow上的@Steven天才答案:logger wrapper best practice
public interface ILogger
{
void Log(LogEntry entry);
}
public class SerilogLogger<T> : ILogger
{
private readonly Serilog.ILogger _logger;
public SerilogLogger()
{
_logger = new LoggerConfiguration()
.WriteTo
.Trace(LogEventLevel.Information)
.CreateLogger()
.ForContext(typeof (T));
}
public void Log(LogEntry entry)
{
/* Logging abstraction handling */
}
}
public static class ContainerExtensions {
public static void RegisterLogging(this Container container)
{
container.RegisterConditional(
typeof(ILogger),
c => typeof(SerilogLogger<>).MakeGenericType(c.Consumer.ImplementationType),
Lifestyle.Singleton,
c => true);
}
}
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在你的作文根:
var container = new Container();
container.RegisterLogging();
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