Art*_*hiu 6 php mysql laravel laravel-5
在我的数据库中有4名学生:
1st Student's created_at = 2016-05-12 02:23:51
2nd Student's created_at = 2016-05-27 07:37:45
3rd Student's created_at = 2016-05-29 07:40:29
4th Student's created_at = 2016-05-29 07:50:05
为什么我的代码只返回第一名学生?
$students = Student::select('id as ID_NO', 'fname as Firstname', 'lname as Lastname', 'created_at')
->whereBetween('created_at',
[Carbon::createFromDate(2016, 5, 12)->toDateString(),
Carbon::createFromDate(2016, 5, 27)->toDateString()])
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第一名和第二名学生应该退回."to"部分包含在WhereBetween或我的代码有什么问题吗?
我需要你的帮助.提前致谢!
Laravel搜索between,这意味着它将获取2016-05-12 00:00:00和之间的所有行2016-05-27 00:00:00。在处创建了第二个用户2016-05-27 07:37:45,该用户不在范围内,因此Laravel不会获取它。
使用它并尝试是否可行:
$students = Student::select('id as ID_NO', 'fname as Firstname', 'lname as Lastname', 'created_at')
->whereBetween('created_at',
[Carbon::createFromDate(2016, 5, 12)->toDateString(),
Carbon::createFromDate(2016, 5, 28)->toDateString()])
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希望这有效!
你需要格式化你created_at的Y-m-d格式。请看变化:
$students = Student::select('id as ID_NO', 'fname as Firstname', 'lname as Lastname', 'created_at')
->whereBetween(DB::raw('date(created_at)'),
[Carbon::createFromDate(2016, 5, 12)->toDateString(),
Carbon::createFromDate(2016, 5, 27)->toDateString()])
Run Code Online (Sandbox Code Playgroud)
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