有没有办法在凤凰城定义自定义路线？

Question

假设我想创建一个resources向它添加几个自定义动作,rails中的模拟是:

resources :tasks do
  member do
    get :implement
  end
end

这不仅会给我带来7条标准路线,还会带来1条新路线:

GET /tasks/:id/implement

我怎么能在凤凰城做到这一点？

Answer 1

我想Dogbert稍微改善一下答案:

resources "/tasks", TaskController do
  get "/implement", TaskController, :implement, as: :implement
end

唯一的补充是as: :implement在路线的尽头.

因此,您将获得命名task_implement_path而不是丑陋的路线task_task_path.

Answer 2

你可以get在do块里面添加一个resources.

网络/ router.ex

resources "/tasks", TaskController do
  get "/implement", TaskController, :implement
end

$ mix phoenix.routes

     task_path  GET     /tasks                     MyApp.TaskController :index
     task_path  GET     /tasks/:id/edit            MyApp.TaskController :edit
     task_path  GET     /tasks/new                 MyApp.TaskController :new
     task_path  GET     /tasks/:id                 MyApp.TaskController :show
     task_path  POST    /tasks                     MyApp.TaskController :create
     task_path  PATCH   /tasks/:id                 MyApp.TaskController :update
                PUT     /tasks/:id                 MyApp.TaskController :update
     task_path  DELETE  /tasks/:id                 MyApp.TaskController :delete
task_task_path  GET     /tasks/:task_id/implement  MyApp.TaskController :implement

Answer 3

这是另一个解决方案:

scope "/tasks" do
  get "/:id/implement", TasksController, :implement
  get "/done", TasksController, :done
end
resources "/tasks", TasksController

该implement操作具有成员路由,并且该done操作具有收集路由.

您可以通过此函数调用获取前者的路径:

tasks_path(@conn, :implement, task)

请注意,您应该在块之后放置该resources行.否则,凤凰城认为是行动的道路.scope/tasks/doneshow