在nodejs脚本中,我有以下代码同步调用并从我调用的shell脚本返回stdout:
var sh = require('shelljs');
... some code
var output = sh.exec('./someshellscript.sh', {silent:true}).stdout;
console.log(output);
... some more code (that shouldnt run until the script is complete)
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我还可以运行以下脚本,它将返回stderr:
var sh = require('shelljs');
... some code
var output = sh.exec('./someshellscript.sh', {silent:true}).stderr;
console.log(output);
... some more code (that shouldnt run until the script is complete)
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但是我希望在同步调用中同时接收stdout和stderr.它可能是我在这里失踪的非常明显但我无法解决的问题.
我认为你曾经能够在以前的版本中运行以下命令,但这只是现在返回undefined:
var sh = require('shelljs');
... some code
var output = sh.exec('./someshellscript.sh', {silent:true}).output;
console.log(output);
... some more code (that shouldnt run until the script is complete)
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相关软件版本为:
任何帮助表示感谢.
从README方法exec(command [, options] [, callback])
除非另有说明,否则同步执行给定的命令.[...],返回{code:...,stdout:...,stderr:...}形式的对象.
因此
const { stdout, stderr, code } = sh.exec('./someshellscript.sh', { silent: true })
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