从Mongo验证JSON？

Question

我想检查用户输入的文本是否是有效的JSON.我知道我可以使用这样的东西轻松地做到这一点:

function IsJsonString(str) {
    try {
        JSON.parse(str);
    } catch (e) {
        return false;
    }
    return true;
}

我的问题是与来自蒙戈,它被包裹在JSON ObjectId,ISODate即:

{
    "_id" : ObjectId("5733b42c66beadec3cbcb9a4"),
    "date" : ISODate("2016-05-11T22:37:32.341Z"),
    "name" : "KJ"
}

这不是有效的JSON.如何在允许上述内容的同时验证JSON？

Answer 1

你可以用字符串替换裸函数调用，像这样

function IsJsonLikeString(str) {
  str = str.replace(/(\w+)\("([^"]+)"\)/g, '"$1(\"$2\")"');
  try {
    JSON.parse(str);
  } ...

来自https://regex101.com/r/fW7iH4/#javascript的解释：

/(\w+)\("([^"]+)"\)/g
    1st Capturing group (\w+)
        \w+ match any word character [a-zA-Z0-9_]
            Quantifier: + Between one and unlimited times, as many times as possible, giving back as needed [greedy]
    \( matches the character ( literally
    " matches the characters " literally
    2nd Capturing group ([^"]+)
        [^"]+ match a single character not present in the list below
            Quantifier: + Between one and unlimited times, as many times as possible, giving back as needed [greedy]
            " a single character in the list " literally (case sensitive)
    " matches the characters " literally
    \) matches the character ) literally
    g modifier: global. All matches (don't return on first match)