我正在处理一个现有的c项目(sourceforge上的spglib),我在清理了一些数组初始化后遇到了以下问题:
*检测到glibc* tests/spglibtest:free():下一个大小无效(快):0x08ab46e0***
回溯是:
#0 0xb7fe1424 in __kernel_vsyscall ()
#1 0xb5cfdd61 in raise () from /lib/libc.so.6
#2 0xb5cff5ee in abort () from /lib/libc.so.6
#3 0xb5d397ed in ?? () from /lib/libc.so.6
#4 0xb5d3f7b1 in ?? () from /lib/libc.so.6
#5 0xb5d4052b in ?? () from /lib/libc.so.6
#6 0xb5d441cd in free () from /lib/libc.so.6
#7 0xb6681484 in sym_get_multiplicity (cell=0xbfffe1f0, symprec=0.050000000000000003) at /git/xtalopt-public/src/spglib/symmetry.c:168
#8 0xb6680550 in spg_find_primitive (lattice=0xbfffe2a8, position=0x813c6f0, types=0x813c700, num_atom=2, symprec=0.050000000000000003)
at /git/xtalopt-public/src/spglib/spglib.c:253
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错误发生在下面的"免费(反式)"行中:
int sym_get_multiplicity(const Cell *cell, const double symprec)
{
int i, rc;
double **trans;
trans = (double**)malloc(cell->size * sizeof(double*));
for (i = 0; i < cell->size; i++) {
trans[i] = (double*)malloc(3 * sizeof(double));
}
rc = get_translation(&trans[0][0], identity, cell, symprec);
for (i = 0; i < cell->size; i++) {
free(trans[i]);
}
free(trans);
return rc;
}
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get_translation将值分配给trans,如下所示:
static int get_translation(double trans[][3], const int rot[3][3], const Cell *cell,
const double symprec)
{
...
for (j = 0; j < 3; j++) {
trans[num_trans][j] = someDouble;
}
...
}
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在get_translation中写入数组时,Valgrind显示以下内容:
==17929== Invalid write of size 8
==17929== at 0x56BE8A7: get_translation (symmetry.c:285)
==17929== by 0x56BE44B: sym_get_multiplicity (symmetry.c:163)
...
==17929== Address 0x9cb5868 is 0 bytes after a block of size 8 alloc'd
==17929== at 0x4024918: malloc (in /usr/lib/valgrind/vgpreload_memcheck-x86-linux.so)
==17929== by 0x56BE3F7: sym_get_multiplicity (symmetry.c:158)
....
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这告诉我,它试图在已经分配的内存的末尾写入trans,但是它写入trans [0] [0],而trans是维度[2] [3].这应该有用,AFAIK,任何人都可以看到我失踪的东西吗?
您的类型是错误的,您不能将指针传递给指向数组数组的函数的指针数组(即指向数组的指针).
对于您的签名get_translation,您需要:
double (*trans)[3] = malloc(cell->size * sizeof(double[3]));
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