错误的结果在JavaScript中解析日期

Question

我从json字符串开始,看起来像: ["2016-05-28", "2016-05-29", "2016-05-30", "2016-05-31"]

我正在尝试将其转换为Saturday 5/28 Sunday 5/29.

我查看了这些答案并试图实现相同的目的: 为什么Date.parse会给出不正确的结果？并将 字符串中的日期转换为日期对象以插入数据库.

但我得到了错误的一天输出.5/28出现Tuesday, 5/28在星期六.

JSFiddle:https://jsfiddle.net/pum40hyx/

这是我的代码,我将日期转换为我想要的字符串:

function convertToNiceDate(inputDate)
{
    var days = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"];
    var splitString = inputDate.split("-");

    currentDate = new Date(splitString[0], splitString[1], splitString[2]);
    var day = currentDate.getDate();
    var month = currentDate.getMonth();

    //this is the problematic line!
    var dayOfWeek = days[currentDate.getDay()];

    var dateString = dayOfWeek + ", " + month + "/" + day;
    return dateString;
}

Answer 1

几个月的范围是使用格式0-11构建新Date的时间new Date(year, month[, day[, ...).所以1月应该是0,而不是1字符串分裂时.

month: 表示月份的整数值,从1月的0开始到12月的11.

这是一个证明这一点的hacky解决方案:

function convertToNiceDate(inputDate)
{
    var days = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"];
    var splitString = inputDate.split("-");

    currentDate = new Date(splitString[0], +splitString[1]-1, splitString[2]);
    var day = currentDate.getDate();
    var month = currentDate.getMonth() + 1;

    //this is the problematic line!
    var dayOfWeek = days[currentDate.getDay()];

    var dateString = dayOfWeek + ", " + month + "/" + day;
    return dateString;
}

document.body.innerHTML = convertToNiceDate('2016-01-01');

您还可以执行以下操作:

function convertToNiceDate(inputDate) {
  var days = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"];
  var splitString = inputDate.split("-");

  currentDate = new Date(inputDate);
  var day = currentDate.getUTCDate();
  var month = currentDate.getUTCMonth() + 1;

  //this is the problematic line!
  var dayOfWeek = days[currentDate.getUTCDay()];

  var dateString = dayOfWeek + ", " + month + "/" + day;
  return dateString;
}

document.body.innerHTML = convertToNiceDate('2016-01-01');