Sid*_*Sid 2 apache-spark pyspark pyspark-sql
我是Spark编程的新手,有一个场景可以在输入中出现一组值时分配一个值.下面是我将用来完成任务的传统SQL代码.需要在Spark中做同样的事情.
Sql代码:
SELECT CASE WHEN c.Number IN ( '1121231', '31242323' ) THEN 1
ELSE 2 END AS Test
FROM Input c
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我知道when在一个条件下使用spark.
Input.select(when(Input.Number==1121231,1).otherwise(2).alias("Test")).show()
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我假设您正在使用Spark DataFrames,而不是RDD.需要注意的一点是,您可以直接在DataFrame上运行SQL查询:
# register the DataFrame so we can refer to it in queries
sqlContext.registerDataFrameAsTable(df, "df")
# put your SQL query in a string
query = """SELECT CASE WHEN
df.number IN ('1121231', '31242323') THEN 1 ELSE 2 END AS test
FROM df"""
result = sqlContext.sql(query)
result.show()
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您还可以select通过创建模仿查询的case语句的用户定义函数来使用:
from pyspark.sql.types import *
from pyspark.sql.functions import udf
# need to pass inner function through udf() so it can operate on Columns
# also need to specify return type
column_in_list = udf(
lambda column: 1 if column in ['1121231', '31242323'] else 2,
IntegerType()
)
# call function on column, name resulting column "transformed"
result = df.select(column_in_list(df.number).alias("transformed"))
result.show()
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