如何使用 string.replace() 删除停用词

Question

我有一个文本文件，我正在计算行数、字符数和单词数。如何通过使用 string.replace() 删除停用词（例如 (the, for, a)）来清理数据

我现在有下面的代码。

前任。如果文本文件包含以下行：

"The only words to count are Apple and Grapes for this text"

它应该输出：

2 Apple
2 Grapes
1 words
1 only
1 text

并且不应该输出这样的词：

• 这
• 到
• 是
• 为了
• 这个

以下是我目前拥有的代码。

# Open the input file
fname = open('2013_honda_accord.txt', 'r').read()

# COUNT CHARACTERS
num_chars = len(fname)

# COUNT LINES 
num_lines = fname.count('\n')

#COUNT WORDS
fname = fname.lower() # convert the text to lower first
words = fname.split()
d = {}
for w in words:
    # if the word is repeated - start count
    if w in d:    
       d[w] += 1
    # if the word is only used once then give it a count of 1
    else:
       d[w] = 1

# Add the sum of all the repeated words 
num_words = sum(d[w] for w in d)

lst = [(d[w], w) for w in d]
# sort the list of words in alpha for the same count 
lst.sort()
# list word count from greatest to lowest (will also show the sort in reserve order Z-A)
lst.reverse()

# output the total number of characters
print('Your input file has characters = ' + str(num_chars))
# output the total number of lines
print('Your input file has num_lines = ' + str(num_lines))
# output the total number of words
print('Your input file has num_words = ' + str(num_words))

print('\n The 30 most frequent words are \n')

# print the number of words as a count from the text file with the sum of each word used within the text
i = 1
for count, word in lst[:10000]:
print('%2s.  %4s %s' % (i, count, word))
i += 1

谢谢

Answer 1

打开并读取文件 ( fname = open('2013_honda_accord.txt', 'r').read()) 后，您可以放置​​以下代码：

blacklist = ["the", "to", "are", "for", "this"]  # Blacklist of words to be filtered out
for word in blacklist:
    fname = fname.replace(word, "")

# The above causes multiple spaces in the text (e.g. '  Apple    Grapes  Apple')
while "  " in fname:
    fname = fname.replace("  ", " ")  # Replace double spaces by one while double spaces are in text

编辑： 为了避免包含不需要的单词的单词出现问题，您可以这样做（假设单词在句子中间）：

blacklist = ["the", "to", "are", "for", "this"]  # Blacklist of words to be filtered out
for word in blacklist:
    fname = fname.replace(" " + word + " ", " ")
# Or .'!? ect.

这里不需要检查双空格。

希望这可以帮助！