SSE与函数的陌生感

Str*_*ers 6 sse d inline-assembly

我一直在玩D的内联汇编程序和SSE,但发现了一些我不理解的东西.当我尝试在声明后立即添加两个float4向量时,计算是正确的.如果我把计算放在一个单独的函数中,我得到一系列的nans.

//function contents identical to code section in unittest
float4 add(float4 lhs, float4 rhs)
{
    float4 res;
    auto lhs_addr = &lhs;
    auto rhs_addr = &rhs;
    asm
    {
        mov RAX, lhs_addr;
        mov RBX, rhs_addr;
        movups XMM0, [RAX];
        movups XMM1, [RBX];

        addps XMM0, XMM1;
        movups res, XMM0;
    }
    return res;
}

unittest
{
    float4 lhs = {1, 2, 3, 4};
    float4 rhs = {4, 3, 2, 1};

    println(add(lhs, rhs)); //float4(nan, nan, nan, nan)

    //identical code starts here
    float4 res;
    auto lhs_addr = &lhs;
    auto rhs_addr = &rhs;
    asm
    {
        mov RAX, lhs_addr;
        mov RBX, rhs_addr;
        movups XMM0, [RAX];
        movups XMM1, [RBX];

        addps XMM0, XMM1;
        movups res, XMM0;
    } //end identical code
    println(res); //float4(5, 5, 5, 5)
}
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该组件在功能上与此链接相同(据我所知).

编辑:我正在使用自定义float4结构(现在,它只是一个数组),因为我希望能够有一个类似的添加函数float4 add(float4 lhs, float rhs).目前,这会导致编译器错误,如下所示:

错误:预期浮点常量表达式而不是rhs

注意:我正在使用DMD 2.071.0

Koz*_*i11 2

你的代码很奇怪,你使用什么版本的dmd?这按预期工作:

import std.stdio;
import core.simd;

float4 add(float4 lhs, float4 rhs)
{
    float4 res;
    auto lhs_addr = &lhs;
    auto rhs_addr = &rhs;
    asm
    {
        mov RAX, lhs_addr;
        mov RBX, rhs_addr;
        movups XMM0, [RAX];
        movups XMM1, [RBX];

        addps XMM0, XMM1;
        movups res, XMM0;
    }
    return res;
}

void main()
{
    float4 lhs = [1, 2, 3, 4];
    float4 rhs = [4, 3, 2, 1];

    auto r = add(lhs, rhs);
    writeln(r.array); //float4(5, 5, 5, 5)

    //identical code starts here
    float4 res;
    auto lhs_addr = &lhs;
    auto rhs_addr = &rhs;
    asm
    {
        mov RAX, lhs_addr;
        mov RBX, rhs_addr;
        movups XMM0, [RAX];
        movups XMM1, [RBX];

        addps XMM0, XMM1;
        movups res, XMM0;
    } //end identical code
    writeln(res.array); //float4(5, 5, 5, 5)
}
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