Abd*_*rim 4 javascript xpath json jsonpath typescript
Run Code Online (Sandbox Code Playgroud){ "response": { "result": { "Countries": { "row": [ { "no": "1", "FL": [ { "content": "USA", "val": "Country" }, { "content": "Barack Obama", "val": "President" } ] }, { "no": "2", "FL": [ { "content": "Cuba", "val": "Country" }, { "content": "Raul Castro", "val": "President" } ] } ] } } } }
{ presidents: [
{ "name": "Barack Obama"}
]
}
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假设您正在将响应加载到变量数据中:
var data = {
"response" : {
"result" : {
"Countries" : {
"row" : [{
"no" : "1",
"FL" : [{
"content" : "USA",
"val" : "Country"
}, {
"content" : "Barack Obama",
"val" : "President"
}
]
}, {
"no" : "2",
"FL" : [{
"content" : "Cuba",
"val" : "Country"
}, {
"content" : "Raul Castro",
"val" : "President"
}
]
}
]
}
}
}
};
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然后,您可以像这样过滤数据:
data.response.result.Countries.row.filter(function (el) {
return (el.FL[0].content == "USA");
})[0].FL[1];
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到达,得到:
{
"content" : "Barack Obama",
"val" : "President"
}
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要获取名称,只需指定“内容”
data.response.result.Countries.row.filter(function(el){
return (el.FL[0].content == "USA");
})[0].FL[1].content;
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编辑 1
可以像字符串一样搜索 json 对象。
如果我们知道元素没有子元素,那么我们可以使用这样的方法:
function find(query,obj) {
var str = JSON.stringify(obj);
var start = str.substr(0,str.indexOf(query)).lastIndexOf('{');
var end = str.substr(start,str.length).indexOf('}');
return str.substr(start,end);
}
console.log(find('"content":"USA"',data))
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