"指向最后一个元素的指针"的更漂亮的语法,std :: vector？

Question

我想知道是否有更漂亮的语法来获得C++向量中最后一个元素的普通指针(不是迭代器)

std::vector<int> vec;

int* ptrToLastOne = &(*(vec.end() - 1)) ;

// the other way I could see was
int* ptrToLastOne2 = &vec[ vec.size()-1 ] ;

但这些都不是很好看!

Answer 1

int* ptrToLastOne = &vec.back(); // precondition: !vec.empty()

Answer 2

int* ptrToLast = &(vec.back()); // Assuming the vector is not empty.

Answer 3

其他一些选择：

int* ptrToLast = &*vec.rbegin();

要么

int* ptrToLast = &*boost::prev(vec.end());