Dav*_*vid 25 iphone uiscrollview gesture swipe
我正在尝试识别左/右滑动手势UIScrollView.我试图创建UISwipeGestureRecognizers并将它们与滚动视图相关联.它的工作原理很少见.大部分时间我都没有被召唤.为什么?
如何可靠地左/右滑动工作?我可以使用手势识别器,还是我必须以某种方式处理它touchesBegan/Ended
谢谢
Dav*_*vid 42
弄清楚了.在我的例子中,我的UIScrollView包含一个允许缩放的UIImage.显然这意味着滚动已启用且UIScrollView难以区分用于滚动和滑动的手势(下一个,上一个图像).
在我的情况下,关键是在图像未放大时禁用滚动视图中的滚动,并在放大图像时重新设置它.这提供了预期的行为.
关键部分是将以下内容放在滚动视图的委托中:
- (void)scrollViewDidZoom:(UIScrollView *)scrollView {
if (scrollView.zoomScale!=1.0) {
// Zooming, enable scrolling
scrollView.scrollEnabled = TRUE;
} else {
// Not zoomed, disable scrolling so gestures get used instead
scrollView.scrollEnabled = FALSE;
}
}
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我还必须在禁用滚动的情况下初始化滚动视图.要启用缩放,只需在委托调用上提供图像,
- (UIView *)viewForZoomingInScrollView:(UIScrollView *)scrollView {
// Return the scroll view
return myImage;
}
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并在viewDidLoad中设置一些参数用于缩放和设置手势识别器
- (void)viewDidLoad {
[super viewDidLoad];
myScrollView.contentSize = CGSizeMake(myImage.frame.size.width, myImage.frame.size.height);
myScrollView.maximumZoomScale = 4.0;
myScrollView.minimumZoomScale = 1.0;
myScrollView.clipsToBounds = YES;
myScrollView.delegate = self;
[myScrollView addSubview:myImage];
[self setWantsFullScreenLayout:TRUE];
myScrollView.scrollEnabled = FALSE;
UISwipeGestureRecognizer *recognizer =
[[UISwipeGestureRecognizer alloc] initWithTarget:self action:@selector(handleSwipeFrom:)];
recognizer.delaysTouchesBegan = TRUE;
[myScrollView addGestureRecognizer:recognizer];
[recognizer release];
recognizer = [[UISwipeGestureRecognizer alloc] initWithTarget:self action:@selector(handleSwipeFrom:)];
recognizer.direction = UISwipeGestureRecognizerDirectionLeft;
[myScrollView addGestureRecognizer:recognizer];
[recognizer release];
[myScrollView delaysContentTouches];
}
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Ale*_*kov 29
UIScrollView *scrollView = ...
UISwipeGestureRecognizer *mySwipe = ...
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解决此问题的正确解决方案是添加一行代码:
[scrollView.panGestureRecognizer requireGestureRecognizerToFail:mySwipe]
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Swift版本:
scrollView.panGestureRecognizer.requireGestureRecognizerToFail(mySwipe)
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Swift4版本:
scrollView.panGestureRecognizer.require(toFail: mySwipe!);
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