jmk*_*k22 5 c# json restsharp json-deserialization
我正在尝试反序列化从 RestSharp 调用 API 返回的 JSON。
这是一个 C# 控制台应用程序。到目前为止,这是我的代码:
using System;
using RestSharp;
using RestSharp.Authenticators;
using Newtonsoft.Json.Linq;
using Newtonsoft.Json;
using RestSharp.Deserializers;
using System.Collections.Generic;
namespace TwilioTest
{
class Program
{
static void Main(string[] args)
{
var client = new RestClient("https://api.twilio.com/2010-04-01");
var request = new RestRequest("Accounts/{{Account Sid}}/Messages.json", Method.GET);
request.AddParameter("To", "{{phone number}}");
request.AddParameter("From", "{{phone number}}");
client.Authenticator = new HttpBasicAuthenticator("{{account sid}}", "{{auth token}}");
var response = client.Execute(request);
var jsonResponse = JsonConvert.DeserializeObject(response.Content);
Console.WriteLine(jsonResponse);
}
}
}
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响应是 JSON 格式的消息列表,键包括"to"、"from"、"body"和"status"。看起来是这样的:
{
"to": "{{phone number}}",
"from": "{{phone number}}",
"body": "Sent from your Twilio trial account - Message 1!",
"status": "delivered"
},
{
"to": "{{phone number}}",
"from": "{{phone number}}",
"body": "Sent from your Twilio trial account - Message 2",
"status": "delivered"
},
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我想将其转换为一个Message对象数组,其中的Message类如下所示:
class Message
{
public string To { get; set; }
public string From { get; set; }
public string Body { get; set; }
public string Status { get; set; }
}
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我一直在寻找如何将 JSON 转换为对象,并找到了此页面: http: //blog.atavisticsoftware.com/2014/02/using-restsharp-to-deserialize-json.html。该页面上的第三个示例符合我想要的内容。
我对程序做了一些更改,现在它看起来像这样:
class Program
{
static void Main(string[] args)
{
// same as above until this point
...
var response = client.Execute(request);
JsonDeserializer deserial = new JsonDeserializer();
var messageList = deserial.Deserialize<List<Message>>(response);
foreach (Message element in messageList)
{
Console.WriteLine("To: {0}", element.To);
Console.WriteLine("From: {0}", element.From);
Console.WriteLine("Body: {0}", element.Body);
}
Console.ReadLine();
}
}
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但是,messageList当我运行程序时,它是空的。将 JSON 响应转换为对象列表时我缺少什么?RestSharp 文档使它看起来相当简单。
我对 RestSharp 不太了解,但你可以这样获取响应内容字符串:
\n\nvar responseContent = client.Execute(request).Content;\nRun Code Online (Sandbox Code Playgroud)\n\n并使用Json.Net反序列化你的 json 字符串:
\n\nJObject jsonResponse = (JObject)JsonConvert.DeserializeObject(response.Content);\nvar messageList = JsonConvert.DeserializeObject<List<Message>>(jsonResponse["messages"].ToString()\xe2\x80\x8c\xe2\x80\x8b);\nRun Code Online (Sandbox Code Playgroud)\n