自定义Zuul异常

Question

我在Zuul有一个场景,URL路由的服务也可能已关闭.因此,响应主体在JSON主体响应中被抛出500 HTTP Status和ZuulException.

{
  "timestamp": 1459973637928,
  "status": 500,
  "error": "Internal Server Error",
  "exception": "com.netflix.zuul.exception.ZuulException",
  "message": "Forwarding error"
}

我想要做的就是自定义或删除JSON响应,并可能更改HTTP状态代码.

我试图用@ControllerAdvice创建一个异常处理程序,但处理程序没有抓住异常.

更新:

所以我扩展了Zuul过滤器,我可以看到它在执行错误后进入run方法,然后如何更改响应.以下是我到目前为止所得到的.我在某处读到了有关SendErrorFilter的内容,但我如何实现它以及它做了什么？

public class CustomFilter extends ZuulFilter {

    @Override
    public String filterType() {
        return "post";
    }

    @Override
    public int filterOrder() {

        return 1;
    }

    @Override
    public boolean shouldFilter() {
        return true;
    }

    @Override
    public Object run() {
        final RequestContext ctx = RequestContext.getCurrentContext();
        final HttpServletResponse response = ctx.getResponse();
        if (HttpStatus.INTERNAL_SERVER_ERROR.value() == ctx.getResponse().getStatus()) {
            try {
                response.sendError(404, "Error Error"); //trying to change the response will need to throw a JSON body.
            } catch (final IOException e) {
                e.printStackTrace();
            } ;
        }

        return null;
    }

将此添加到具有@EnableZuulProxy的类中

@Bean
public CustomFilter customFilter() {
    return new CustomFilter();
}

Answer 1

我们终于得到了这个工作[由我的一位同事编写]: -

public class CustomErrorFilter extends ZuulFilter {

    private static final Logger LOG = LoggerFactory.getLogger(CustomErrorFilter.class);
    @Override
    public String filterType() {
        return "post";
    }

    @Override
    public int filterOrder() {
        return -1; // Needs to run before SendErrorFilter which has filterOrder == 0
    }

    @Override
    public boolean shouldFilter() {
        // only forward to errorPath if it hasn't been forwarded to already
        return RequestContext.getCurrentContext().containsKey("error.status_code");
    }

    @Override
    public Object run() {
        try {
            RequestContext ctx = RequestContext.getCurrentContext();
            Object e = ctx.get("error.exception");

            if (e != null && e instanceof ZuulException) {
                ZuulException zuulException = (ZuulException)e;
                LOG.error("Zuul failure detected: " + zuulException.getMessage(), zuulException);

                // Remove error code to prevent further error handling in follow up filters
                ctx.remove("error.status_code");

                // Populate context with new response values
                ctx.setResponseBody(“Overriding Zuul Exception Body”);
                ctx.getResponse().setContentType("application/json");
                ctx.setResponseStatusCode(500); //Can set any error code as excepted
            }
        }
        catch (Exception ex) {
            LOG.error("Exception filtering in custom error filter", ex);
            ReflectionUtils.rethrowRuntimeException(ex);
        }
        return null;
    }
}

Answer 2

Zuul RequestContext 不包含本答案中error.exception提到的。 最新的 Zuul 错误过滤器：

@Component
public class ErrorFilter extends ZuulFilter {
    private static final Logger LOG = LoggerFactory.getLogger(ErrorFilter.class);

    private static final String FILTER_TYPE = "error";
    private static final String THROWABLE_KEY = "throwable";
    private static final int FILTER_ORDER = -1;

    @Override
    public String filterType() {
        return FILTER_TYPE;
    }

    @Override
    public int filterOrder() {
        return FILTER_ORDER;
    }

    @Override
    public boolean shouldFilter() {
        return true;
    }

    @Override
    public Object run() {
        final RequestContext context = RequestContext.getCurrentContext();
        final Object throwable = context.get(THROWABLE_KEY);

        if (throwable instanceof ZuulException) {
            final ZuulException zuulException = (ZuulException) throwable;
            LOG.error("Zuul failure detected: " + zuulException.getMessage());

            // remove error code to prevent further error handling in follow up filters
            context.remove(THROWABLE_KEY);

            // populate context with new response values
            context.setResponseBody("Overriding Zuul Exception Body");
            context.getResponse().setContentType("application/json");
            // can set any error code as excepted
            context.setResponseStatusCode(503);
        }
        return null;
    }
}

Answer 3

我有同样的问题,能够以更简单的方式解决它

把它放到你的Filter run()方法中

    if (<your condition>) {
        ZuulException zuulException = new ZuulException("User message", statusCode, "Error Details message");
        throw new ZuulRuntimeException(zuulException);
    }

和SendErrorFilter将提供给用户的消息与期望的statusCode.

异常模式中的此异常看起来并不完美,但它在此处起作用.