avi*_*avi 2 r classification machine-learning decision-tree
我需要从决策树中的规则中提取信息。我在 R 中使用 rpart 包。我在包中使用演示数据来解释我的要求:
data(stagec)
fit<- rpart(formula = pgstat ~ age + eet + g2 + grade + gleason + ploidy, data = stagec, method = "class", control=rpart.control(cp=0.05))
fit
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印花合身展示
n= 146
node), split, n, loss, yval, (yprob)
* denotes terminal node
1) root 146 54 0 (0.6301370 0.3698630)
2) grade< 2.5 61 9 0 (0.8524590 0.1475410) *
3) grade>=2.5 85 40 1 (0.4705882 0.5294118)
6) g2< 13.2 40 17 0 (0.5750000 0.4250000)
12) ploidy=diploid,tetraploid 31 11 0 (0.6451613 0.3548387) *
13) ploidy=aneuploid 9 3 1 (0.3333333 0.6666667) *
7) g2>=13.2 45 17 1 (0.3777778 0.6222222)
14) g2>=17.91 22 8 0 (0.6363636 0.3636364) *
15) g2< 17.91 23 3 1 (0.1304348 0.8695652) *
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例如,我想为第 12 个节点获取如下信息
如果等级>=2.5 且 g2<13.2 且倍性为(二倍体、四倍体),则以 65% 的置信度预测 0 级。任何关于此的指示都会非常有帮助。
谢谢
该
rpart.plot
包3.0版(2018日)有一个函数
rpart.rules生成一组规则的树。例如
library(rpart.plot)
data(stagec)
fit <- rpart(formula = pgstat ~ ., data = stagec, method = "class", control=rpart.control(cp=0.05))
rpart.rules(fit)
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给
pgstat
0.15 when grade < 3
0.35 when grade >= 3 & g2 < 13 & ploidy is diploid or tetraploid
0.36 when grade >= 3 & g2 >= 18
0.67 when grade >= 3 & g2 < 13 & ploidy is aneuploid
0.87 when grade >= 3 & g2 is 13 to 18
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和
rpart.rules(fit, roundint=FALSE, clip.facs=TRUE)
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给
pgstat
0.15 when grade < 2.5
0.35 when grade >= 2.5 & g2 < 13 & diploid or tetraploid
0.36 when grade >= 2.5 & g2 >= 18
0.67 when grade >= 2.5 & g2 < 13 & aneuploid
0.87 when grade >= 2.5 & g2 is 13 to 18
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有关更多示例,请参阅rpart.plot 小插图的第 4 章 。
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