Python Selenium单击下一步按钮直到结束

Question

这是我的第一个问题的后续问题,我正在尝试抓取一个网站并点击Selenium next(直到它无法点击)并收集结果.

这是带有按钮的网站的html标签:

<div class="pager results-display">
  <span class="action-btn prev inactive" data-page="1">Prev</span>
  <span class="action-btn inactive" data-page="1">1</span>  # Currently in page 1 thus inactive
  <span class="action-btn" data-page="2">2</span>
  <span class="action-btn" data-page="3">3</span> 
  <span class="action-btn" data-page="4">4</span>
  <span class="action-btn" data-page="5">5</span>
  <span class="action-btn" data-page="6">6</span>
  <span class="action-btn" data-page="7">7</span>
  <span class="action-btn" data-page="8">8</span> 
  <span class="action-btn" data-page="9">9</span>
  <span class="action-btn" data-page="10">10</span>
  <span class="action-btn" data-page="11">11</span> 
  <span class="action-btn" data-page="12">12</span>
  <span class="action-btn" data-page="13">13</span>
  <span class="action-btn" data-page="14">14</span>
  <span class="action-btn next" data-page="2">Next</span>
</div>
<div class="no-results-display hidden" style="display: none;">
                    No companies matched your search. Try again.
                </div>

我试过这段代码:

elm = driver.find_element_by_name('pager results-display')
elm.click()

而且我也检查了这个问题,但仍然无法解决它.

有什么想法吗？

Answer 1

pager results-display实际上是属于按钮的父元素的两个类.它们不是name属性,find_element_by_name无论如何只获得一个名称.尝试

elm = driver.find_element_by_class_name('next')
elm.click()

请注意,如果在单击后DOM已更改,则可能每次都必须重新定位按钮.

只要按钮处于活动状态,单击循环就可以检查buuton是否具有类 inactive

while True:
    elm = driver.find_element_by_class_name('next')
    if 'inactive' in elm.get_attribute('class'):
        break;
    elm.click()