sud*_*ee_ 5 php gridview detailview yii2
我想展示员工在详细视图和gridview中有很多兴趣爱好.
但我得到了一个错误异常 Trying to get property of non-object
这是我的架构代码模型:
应用程序\型号\ TblDataStaff
....
public function getTblDataHobis()
{
return $this->hasMany(TblDataHobies::className(), ['id_staff' => 'id']);
}
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查看代码:查看.
<?= DetailView::widget([
'model' => $model,
'attributes' => [
...
['attribute'=>'namHob','value'=>$model->tblDataHobis->id],
...
],
]) ?>
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指数:
<?= GridView::widget([
'dataProvider' => $dataProvider,
//'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
......
['attribute'=>'namHob','value'=>function($namHob){return $namHob->tblDataHobis->name_hobby;},],
.....
['class' => 'yii\grid\ActionColumn'],
],]);?>
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如何展示员工的许多爱好?
没什么奇怪的,你Trying to get property of non-object只是因为$model->tblDataHobis返回一个TblDataHobies对象数组而出错.
你可以试试这个:
// display hobbies names separated with commas
echo implode(', ', \yii\helpers\ArrayHelper::map($model->tblDataHobis, 'id', 'name_hobby'));
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用于DetailView:
'value' => implode(\yii\helpers\ArrayHelper::map($model->tblDataHobis, 'id', 'name_hobby')),
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用于GridView:
'value' => function($model) {
return implode(\yii\helpers\ArrayHelper::map($model->tblDataHobis, 'id', 'name_hobby')),
},
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