R dplyr - 在所有列中不同

Question

有没有办法指定 dplyr::distinct 应该使用所有列名而不诉诸非标准评估？

df <- data.frame(a=c(1,1,2),b=c(1,1,3))

df %>% distinct(a,b,.keep_all=FALSE)          # behavior I'd like to replicate

对比

df %>% distinct(everything(),.keep_all=FALSE) # with syntax of this form

Answer 1

您可以使用下面的代码区分所有列。

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library(dplyr)\nlibrary(data.table)\n\ndf <- data_frame(\n  id = c(1, 1, 2, 2, 3, 3),\n  value = c("a", "a", "b", "c", "d", "d")\n)\n# A tibble: 6 \xc3\x97 2\n# id value\n# <dbl> <chr>\n# 1     1     a\n# 2     1     a\n# 3     2     b\n# 4     2     c\n# 5     3     d\n# 6     3     d\n\n# distinct with Non-Standard Evaluation\ndf %>% distinct()\n\n# distinct with Standard Evaluation\ndf %>% distinct_()\n\n# Also, you can set the column names with .dots.\ndf %>% distinct_(.dots = names(.))\n# A tibble: 4 \xc3\x97 2\n# id value\n# <dbl> <chr>\n# 1     1     a\n# 2     2     b\n# 3     2     c\n# 4     3     d\n\n# distinct with data.table\nunique(as.data.table(df))\n# id value\n# 1:  1     a\n# 2:  2     b\n# 3:  2     c\n# 4:  3     d\n

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