按钮单击时更改组件状态

Question

以下是HTML.

<script src="https://fbcdn-dragon-a.akamaihd.net/hphotos-ak-xtp1/t39.3284-6/12624079_897774290317920_1379776191_n.js"></script>
<script src="https://fbcdn-dragon-a.akamaihd.net/hphotos-ak-xfp1/t39.3284-6/12624052_751451571621845_431133942_n.js"></script>


<script src="https://cdnjs.cloudflare.com/ajax/libs/babel-core/5.8.24/browser.min.js"></script>

<div class="row" id="container">
  <div class="controls">
    <span class="" id="controls-size">Size : 
        <button id="controls-size-small">SMALL</button>
        <button id="controls-size-med">MEDIUM</button>
        <button id="controls-size-large">LARGE</button>
    </span>

  </div>
  <div id="game-container">
  </div>
</div>

以下是Javscript

var SizeEnum = {
  SMALL: 1,
  MEDIUM: 2,
  LARGE: 3
};

var Board = React.createClass({
      getInitialState: function() {
        return {
          size: SizeEnum.MEDIUM
        };
      },

      componentWillMount: function() {
        if (this.state.size == SizeEnum.SMALL) {
          this.style = {
            width: 600 + 'px',
            height: 320 + 'px',
            margin: 'auto',
            border: '2px solid red'
          }
        } else if (this.state.size == SizeEnum.MEDIUM) {
          this.style = {
            width: 700 + 'px',
            height: 500 + 'px',
            margin: 'auto',
            border: '2px solid red'
          }
        } else if (this.state.size == SizeEnum.LARGE) {
          this.style = {
            width: 900 + 'px',
            height: 720 + 'px',
            margin: 'auto',
            border: '2px solid red'
          }
        }
      },

      render: function() {
          return ( < div style = {
            this.style
          } > < /div>
    )
  }

});

ReactDOM.render(<Board / > , document.getElementById("game-container"));

还有一些CSS

#game-container {
    position: relative;
    margin-top: 32px;
    border: 1px solid black;
    width: 100%;
}

我想要的是,当单击相应的按钮时,Board组件的大小将调整为适当的大小.

我试过这样做

var board = ReactDOM.render(<Board />, document.getElementById("game-container"));

document.getElementById("controls-size-small").onclick = changeBoardSize;
document.getElementById("controls-size-med").onclick = changeBoardSize;
document.getElementById("controls-size-large").onclick = changeBoardSize;

function changeBoardSize(event) {
    var etid = event.target.id;
    console.log(etid);
    if (etid == "controls-size-small") {
        // method 1
        board.state.size = SizeEnum.SMALL;
    } else if (etid == "controls-size-med") {
        // method 2
        board.state.size = SizeEnum.MEDIUM;
        ReactDOM.render(<Board />, document.getElementById("game-container"));
    } else if (etid == "controls-size-small") {
        // method 3
        board.setState({size: SizeEnum.SMALL});
        ReactDOM.render(<Board />, document.getElementById("game-container"));
    }
}

但它不起作用.

Answer 1

你不能像这样设置 React 组件的状态。并且组件应该负责设置自己的状态。

在 Board 组件内，在 componentDidMount 中设置事件侦听器。最好的解决方案是让按钮成为 React 应用程序的一部分，但这超出了这个问题的范围。假设按钮不是 React 应用程序的一部分，然后执行如下操作：

var Board = React.createClass({
  ...
  ...
  componentDidMount: function(){
    var that = this;
    document.getElementById("controls-size-small").addEventListener('click', that.changeBoardSize, false);
    document.getElementById("controls-size-med").addEventListener('click', that.changeBoardSize, false);
    document.getElementById("controls-size-large").addEventListener('click', that.changeBoardSize, false);
  }

  changeBoardSize: function(e){
    /* get the element id and do the enum things here */
    this.setState({
      size: newSize
    });
  }
  render: function(){
    ...
    ...
  }
});

然后只需将所有 componentWillMount 样式的内容移至该render函数即可。

更新

小提琴：https://jsfiddle.net/dannyjolie/r525ux66/