对嵌套对象的javascript数组进行排序

Mo *_*tar 2 javascript arrays sorting jquery object

我是 JavaScript 的新手,我正在尝试尽可能多地学习,但我觉得我正在尝试做的事情已经碰壁了。

我的问题,我有一个对象数组,每个对象是一个商店对象,这是一个“类型”的维修对象,具有维修成本的属性。

我怎样才能按价格排序?到目前为止,请查看我的代码。我需要按价格顺序返回商店对象,因为我仍然需要商店的所有信息,但根据所做的选择按维修价格排序,所以基本上按选择顺序返回商店对象。我不知道这可能是不可能的,任何想法将不胜感激。我提前感谢您的时间。

var vendors = [

  {
    mosShop: {
      samsung: {
        screen: 50,
        button: 10,
        back: 20
      },
      iphone: {
        screen: 10,
        button: 18,
        back: 1
      }
    }
  }, {
    davesShop: {
      samsung: {
        screen: 40,
        button: 5,
        back: 12
      },
      iphone: {
        screen: 18,
        button: 148,
        back: 11
      }

    }
  }


];
var arr = [];
//;
$('#phone,#repair').change(function() {



  var selectedPhone = $('#phone :selected').text().toString();
  var selectRepair = $('#repair :selected').text().toString();




  for (var i = 0; i < vendors.length; i++) {

    var mo = Object.keys(vendors[i]);
    var t = mo.toString()

    var price = vendors[i][t][selectedPhone][selectRepair];

    alert(price)


  }













});
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<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.0/jquery.min.js"></script>
<select id="phone">
  <option value="samsung">samsung</option>
  <option value="iphone">iphone</option>
  <option value="mercedes">blah</option>
  <option value="audi">blah</option>
</select>
<select id="repair">
  <option value="screen">screen</option>
  <option value="button">button</option>
  <option value="back">back</option>
  <option value="audi">blah</option>
</select>

<div id="endresults">

</div>
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`

She*_*ara 5

要根据selectedPhoneand的值对数组进行排序selectRepair,您可以像这样使用本机sort()函数-

function shopPrices(selectedPhone, selectedRepair) {
    return vendors.sort(function(a,b) { 
        var shopA = Object.keys(a)[0];
        var shopB = Object.keys(b)[0];
        return (a[shopA][selectedPhone][selectedRepair] - b[shopB][selectedPhone][selectedRepair]);
    });
} 
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然后你可以简单地通过传递selectedPhoneselectedRepair值来调用函数,如下所示 -

var sorted = shopPrices('samsung','screen');
//Result -> [{"davesShop":{"samsung":{"screen":40,"button":5,"back":12},"iphone":{"screen":18,"button":148,"back":11}}},{"mosShop":{"samsung":{"screen":50,"button":10,"back":20},"iphone":{"screen":10,"button":18,"back":1}}}]

var anotherTest = shopPrices('iphone','screen');
//Result -> [{"mosShop":{"samsung":{"screen":50,"button":10,"back":20},"iphone":{"screen":10,"button":18,"back":1}}},{"davesShop":{"samsung":{"screen":40,"button":5,"back":12},"iphone":{"screen":18,"button":148,"back":11}}}]
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希望这可以帮助!

  • `Object.keys(a).toString()` 应该是 `Object.keys(a)[0]`。在数组上调用 `toString()` 并将结果用作属性名称是一种误导。 (3认同)