在ArrayBuffer中存储一个json对象

man*_*ish 4 javascript arraybuffer

想要在其中存储一个json对象 ArrayBuffer

function stringToUint(string) {
    var string = btoa(unescape(encodeURIComponent(string))),
        charList = string.split(''),
        uintArray = [];
    for (var i = 0; i < charList.length; i++) {
        uintArray.push(charList[i].charCodeAt(0));
    }
    return new Uint8Array(uintArray);
}

function uintToString(uintArray) {
    var encodedString = String.fromCharCode.apply(null, uintArray),
        decodedString = decodeURIComponent(escape(atob(encodedString)));
    return decodedString;
}
var str = {'x':'aaaa'},
    enc = stringToUint(str),
    dec = uintToString(enc);

console.log(dec.x);
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console.log(dec.x);正在打印`未定义。我做错了吗?这是jsfiddle http://jsfiddle.net/DQJyX/137/

Amm*_*san 5

因为stringToUint需要一个字符串,并将一个对象传递给它,将转换为{'x':'aaaa'}[Object object]并返回一个表示该对象对象的数组,因此在调用时uintToString,该数组会转换回[Object object]

一个简单的解决方案是在JSON.stringify将对象传递给函数之前使用该对象,然后使用JSON.parse转换为原始对象。

function stringToUint(string) {
    var string = btoa(unescape(encodeURIComponent(string))),
        charList = string.split(''),
        uintArray = [];
    for (var i = 0; i < charList.length; i++) {
        uintArray.push(charList[i].charCodeAt(0));
    }
    return new Uint8Array(uintArray);
}

function uintToString(uintArray) {
    var encodedString = String.fromCharCode.apply(null, uintArray),
        decodedString = decodeURIComponent(escape(atob(encodedString)));
    return decodedString;
}
var str = {'x':'aaaa'},
    enc = stringToUint(JSON.stringify(str)),
    dec = JSON.parse(uintToString(enc));
    
document.write(dec.x);
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