Twi*_*ity 21 java gregorian-calendar
我有一个Map人的生日GregorianCalendar.
例如:
{
motherEmailID=null,
coreType=Ticket,
_NULL=null,
additionalFaclitiesProvided=[],
dateOfBirth=java.util.GregorianCalendar[
time=585340200000,
areFieldsSet=false,
areAllFieldsSet=false,
lenient=true,
zone=sun.util.calendar.ZoneInfo[id="GMT",
offset=0,
dstSavings=0,
useDaylight=false,
transitions=0,
lastRule=null],
firstDayOfWeek=1,
minimalDaysInFirstWeek=1,
ERA=1,
YEAR=1988,
MONTH=6,
WEEK_OF_YEAR=30,
WEEK_OF_MONTH=4,
DAY_OF_MONTH=20,
DAY_OF_YEAR=202,
DAY_OF_WEEK=4,
DAY_OF_WEEK_IN_MONTH=3,
AM_PM=0,
HOUR=0,
HOUR_OF_DAY=0,
MINUTE=0,
SECOND=0,
MILLISECOND=0,
ZONE_OFFSET=19800000,
DST_OFFSET=0],
targetEnd=null,
year_semester=null
}
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我需要一个Date,但在我的数据库中它只是Calendar格式化的.数据库中列的数据类型是DateTime.如何以Date格式获取生日?
Osc*_*Ryz 34
Calendar calendar = ( Calendar ) thatMap.get("dateOfBirth");
Date date = calendar.getTime();
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以下是您可以用来测试它的示例,并看到它可以满足您的需求.
import java.util.*;
import java.text.*;
public class GetDate {
public static void main( String [] args ) {
Map map = new HashMap();
map.put("dateOfBirth", Calendar.getInstance() );
map.put("additionalFaclitiesProvided", new ArrayList() );
/// etc.
System.out.println( map );
Calendar cal = ( Calendar ) map.get("dateOfBirth");
Date date = cal.getTime();
// Addressing your comment:
SimpleDateFormat sdf = new SimpleDateFormat("dd.MM.yyyy");
System.out.println( "The date is: "+ sdf.format( date ) );
}
}
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输出:
java GetDate
{dateOfBirth=java.util.GregorianCalendar[
time=1282824447050,areFieldsSet=true,areAllFieldsSet=true,lenient=true,zone=sun.util.calendar.ZoneInfo[
id="America/Mexico_City",offset=-21600000,dstSavings=3600000,useDaylight=true,transitions=99,lastRule=java.util.SimpleTimeZone[
id=America/Mexico_City,offset=-21600000,dstSavings=3600000,useDaylight=true,startYear=0,startMode=3,startMonth=3,startDay=1,
startDayOfWeek=1,startTime=7200000,startTimeMode=0,endMode=2,endMonth=9,endDay=-1,endDayOfWeek=1,endTime=7200000,endTimeMode=0
]
],firstDayOfWeek=1,minimalDaysInFirstWeek=1,ERA=1,YEAR=2010,MONTH=7,WEEK_OF_YEAR=35,WEEK_OF_MONTH=4,DAY_OF_MONTH=26,DAY_OF_YEAR=238,DAY_OF_WEEK=5,
DAY_OF_WEEK_IN_MONTH=4,AM_PM=0,HOUR=7,HOUR_OF_DAY=7,MINUTE=7,SECOND=27,MILLISECOND=50,ZONE_OFFSET=-21600000,DST_OFFSET=3600000]**, additionalFaclitiesProvided=[]
}
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日期是:2010年8月26日
从java.sql.Date到java.util.Calendar(或java.util.GregorianCalendar)
Calendar cal = new GregorianCalendar();
cal.setTime(date); // java.sql.Date date;
// then set the GregorianCalendar in your map
map.put('dateOfBirth', cal);
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从java.util.Calendar到java.sql.Date
java.sql.Date date = new java.sql.Date(map.get('dateOfBirth').getTimeInMillis());
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**注意**
java.sql.Timestamp是一个兄弟,java.sql.Date并且都延伸java.util.Date,因此你可以使用完全相同的方式.
另外,要将日期字符串转换为日期对象,请使用SimpleDateFormat:
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss", Locale.US);
Date d = sdf.parse("2010-08-26 8:34:00");
Calendar cal = Calendar.getInstance();
cal.setTime(d);
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并扭转它
String dateStr1 = sdf.format(cal.getTime());
// or
String dateStr2 = sdf.format(date); // java.sql.Date / java.util.Date
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