Ron*_*ing 5 c# asp.net gridview export-to-excel closedxml
我正在开发 ASP.NET 4.5 Webform,并且有一个 Gridview (它具有自定义 TemplateField 并从 sqlDataSource 获取数据)
我有这个事件将 gridview 内容导出到 Excel 工作表,它的工作很好,除了创建的文件在用户打开它时发出警告(我理解,因为创建的文件不是实际的 Excel 文件) :
“您尝试打开的文件的格式与文件扩展名指定的格式不同”
protected void btnExport_Excel_Click(object sender, EventArgs e)
{
try
{
Response.Clear();
Response.Buffer = true;
Response.AddHeader("content-disposition", "attachment;filename=GV.xls");
Response.Charset = "";
Response.ContentType = "application/ms-excel";
//Response.ContentType = "application/text";
Response.ContentEncoding = System.Text.Encoding.Unicode;
Response.BinaryWrite(System.Text.Encoding.Unicode.GetPreamble());
using (StringWriter sw = new StringWriter())
{
HtmlTextWriter hw = new HtmlTextWriter(sw);
//To Export all pages
GridView4.AllowPaging = false;
GridView4.AllowSorting = false;
GridView4.ShowFooter = false;
GridView4.DataBind();
//this.BindGrid();
GridView4.HeaderRow.BackColor = Color.White;
foreach (TableCell cell in GridView4.HeaderRow.Cells)
{
cell.BackColor = GridView4.HeaderStyle.BackColor;
}
foreach (GridViewRow row in GridView4.Rows)
{
row.BackColor = Color.White;
foreach (TableCell cell in row.Cells)
{
if (row.RowIndex % 2 == 0)
{
cell.BackColor = GridView4.AlternatingRowStyle.BackColor;
}
else
{
cell.BackColor = GridView4.RowStyle.BackColor;
}
cell.CssClass = "textmode";
}
}
GridView4.RenderControl(hw);
//style to format numbers to string
string style = @"<style> .textmode { } </style>";
Response.Write(style);
Response.Output.Write(sw.ToString());
Response.Flush();
Response.End();
}
//Display message
InfoPanel.Visible = true;
InfoPanel.CssClass = "panel panel-success";
lblMessage.CssClass = "text text-sucess bold";
lblMessage.Text = "File has been exported!";
}
catch (Exception ex)
{
//Display message
InfoPanel.Visible = true;
lblMessage.Text = "<b>An error has occurred. Please try again later!</b></br>" + ex.Message;
lblMessage.CssClass = "text text-danger bold";
InfoPanel.CssClass = "panel panel-danger";
panelResult.Visible = false;
}
}
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Excel .xls 文件中的结果很好(除了标题列之外没有样式,没有页脚,与 Gridview 上显示的完全相同):
我正在寻找另一种方法来避免此警告,因此我看到人们喜欢使用
ClosedXML,因此我将上面的事件替换为以下事件:
protected void ExportExcel(object sender, EventArgs e)
{
DataTable dt = new DataTable("GridView_Data");
foreach(TableCell cell in GridView4.HeaderRow.Cells)
{
dt.Columns.Add(cell.Text);
}
foreach (GridViewRow row in GridView4.Rows)
{
dt.Rows.Add();
for (int i=0; i<row.Cells.Count; i++)
{
dt.Rows[dt.Rows.Count - 1][i] = row.Cells[i].Text;
}
}
using (XLWorkbook wb = new XLWorkbook())
{
wb.Worksheets.Add(dt);
Response.Clear();
Response.Buffer = true;
Response.Charset = "";
Response.ContentType = "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet";
Response.AddHeader("content-disposition", "attachment;filename=GV.xlsx");
using (MemoryStream MyMemoryStream = new MemoryStream())
{
wb.SaveAs(MyMemoryStream);
MyMemoryStream.WriteTo(Response.OutputStream);
Response.Flush();
Response.End();
}
}
}
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结果很糟糕(唯一的好消息是导出的文件是真正的 2007+ Excel 工作表,因此没有警告):

如何使用 ClosedXML 获得上述“良好”结果?
代码第二部分(使用 ClosedXML)的主要问题是,您尝试使用字段列Text的属性。正如您在此处看到的,您只能通过字段列和自动生成的字段列的属性获取字段值。GridViewRowTemplateFieldTextBoundField
要从中获取价值,TemplateField您应该导航到包含价值的内部控件并从中获取价值。
如果您有以下列模板:
<asp:TemplateField>
<ItemTemplate>
<asp:Label ID="labelName" runat="server" Text ='<%# Eval("ABC")%>' ></asp:Label>
</ItemTemplate>
</asp:TemplateField>
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你的代码应该是:
for (int i=0; i<row.Cells.Count; i++)
{
dt.Rows[dt.Rows.Count - 1][i] = (row.Cells[i].FindControl("labelName") as Label).Text;
}
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编辑
您的代码应如下所示:
protected void ExportExcel(object sender, EventArgs e)
{
DataTable dt = new DataTable("GridView_Data");
foreach (DataControlField col in GridView4.Columns)
{
dt.Columns.Add(col.HeaderText);
}
foreach (GridViewRow row in GridView4.Rows)
{
dt.Rows.Add();
for (int i = 0; i < row.Cells.Count; i++)
{
dt.Rows[dt.Rows.Count - 1][i] = (FindControl(row.Cells[i].Controls, "lbl") as Label).Text;
}
}
//your code below is not changed
}
protected Control FindControl(ControlCollection collection, string id)
{
foreach (Control ctrl in collection)
{
if (ctrl.ID == id)
return ctrl;
}
return null;
}
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确保Label使用的所有控件都与以下内容TemplateField相同:ID"lbl"
<asp:TemplateField HeaderText="ID">
<ItemTemplate>
<asp:Label ID="lbl" runat="server" Text ='<%# Eval("ID")%>' ></asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Name">
<ItemTemplate>
<asp:Label ID="lbl" runat="server" Text ='<%# Eval("Name")%>' ></asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Amount">
<ItemTemplate>
<asp:Label ID="lbl" runat="server" Text ='<%# Eval("Amount")%>' ></asp:Label>
</ItemTemplate>
</asp:TemplateField>
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