isFlag而不是isFlag()语法:是否可以在Javascript中使用

Question

在下面的代码中,我定义了Greeter.prototype.isVeryPolite = function(){...用于访问this._isVeryPolite

greeter.isVeryPolite()

但最后的"()"不是非常用户友好.有没有javascript的技巧,能够拥有greeter.isVeryPolite而无需直接访问会员？

https://jsfiddle.net/5r4so2Ld/

var Greeter = (function () {
    function Greeter(message, flag) {
        this._name = message;
        this._isVeryPolite = flag;
    }
    Greeter.prototype.greet = function () {
        if (this._isVeryPolite) {
            return "How do you do, " + this._name;
        }
        else {
            return "Hello " + this._name;
        }
    };
    Greeter.prototype.isVeryPolite = function () {
        return this._isVeryPolite;
    };
    return Greeter;
})();
var greeter = new Greeter("world", true);
var button = document.createElement('button');
button.textContent = "Say Hello";
button.onclick = function () {
    alert(greeter.greet());
    alert(greeter.isVeryPolite());
};
document.body.appendChild(button);

Answer 1

听起来你正在寻找一个吸气剂.一个例子(取自MDN):

var log = ['test'];
var obj = {
  get latest () {
    if (log.length == 0) return undefined;
    return log[log.length - 1]
  }
}
console.log (obj.latest); // Will return "test".