两个日期之间的 Android 通话记录数据和来自同一号码的通话总持续时间。

Question

想要获得今天、昨天、过去 7 天和过去 30 天的通话记录历史记录以及我想显示该特定号码的来电和去电的总持续时间。

假设abc有 3 个呼出和 1 个呼入。我应该得到这些电话的总持续时间。

让我知道我们是否可以通过游标GroupBy或ORDER BY子句获取持续时间并调用日志，而不是循环和添加持续时间。只需给我粗略的结构以获得更好的解决方案，并且可以有效地工作。

         String[] whereValue=null;
        Calendar calendar = Calendar.getInstance();
        String currentDate = String.valueOf(calendar.getTimeInMillis());
        switch (period) {
            case DAY:
                whereValue  = new String[]{getTimeFrom(period),currentDate};
                break;
            case YESTERDAY:
                whereValue  = new String[]{getTimeFrom(period),currentDate};
                break;
            case WEEK:
                whereValue  = new String[]{getTimeFrom(period),currentDate};

                break;
            case MONTH:
                    whereValue  = new String[]{getTimeFrom(period),currentDate};
                break;
            default:
                Log.d(Utils.LOG_TAG, "Error:");
        }
        String strOrder = android.provider.CallLog.Calls.DATE + " DESC";
        Uri callUri = Uri.parse("content://call_log/calls");

        Cursor cur = context.getContentResolver().query(callUri, null, android.provider.CallLog.Calls.DATE+" BETWEEN ? AND ?", whereValue, strOrder);

   String callNumber = cur.getString(cur
                    .getColumnIndex(android.provider.CallLog.Calls.NUMBER));

            String callName = cur
                    .getString(cur
                            .getColumnIndex(android.provider.CallLog.Calls.CACHED_NAME));
      String callType = cur.getString(cur
                    .getColumnIndex(android.provider.CallLog.Calls.TYPE));
            String dir = null;
            int dircode = Integer.parseInt(callType);
            switch (dircode) {
                case CallLog.Calls.OUTGOING_TYPE:
                case CallLog.Calls.INCOMING_TYPE:
                    break;

            }
            String duration = cur.getString(cur
                    .getColumnIndex(android.provider.CallLog.Calls.DURATION));

上面的代码甚至不能用于获取从日期到日期之间的通话记录。有什么帮助吗？

Answer 1

我设法获得了两个日期之间的通话记录。您可以获取今天、昨天、过去 7 天、过去 30 天的通话记录。以及通话的持续时间（来自同一号码的多次通话）

您应该将选择传递为
android.provider.CallLog.Calls.DATE +“ BETWEEN ? AND ?” 和

选择参数

whereValue = new String[]{String.valueOf(calendar1.getTimeInMillis()),String.valueOf(calendar.getTimeInMillis());};

  Map<String, StatEntry> callLogMap1 = new HashMap<>();
            callLogMap1.clear();

            String strOrder1 = android.provider.CallLog.Calls.DATE + " DESC limit 500";

            Uri callUri = Uri.parse("content://call_log/calls");
            Cursor cur = getContentResolver().query(CallLog.Calls.CONTENT_URI, null, android.provider.CallLog.Calls.DATE + " BETWEEN ? AND ?", whereValue,
                    strOrder1);


            if (cur != null) {
                try {
                    while (cur.moveToNext()) {

                        String callNumber = cur.getString(cur.getColumnIndex(android.provider.CallLog.Calls.NUMBER));
                        //    String callDate = cur.getString(cur.getColumnIndex(android.provider.CallLog.Calls.DATE));
                        int duration = cur.getInt(cur.getColumnIndex(android.provider.CallLog.Calls.DURATION));

                        String name = cur.getString(cur.getColumnIndex(CallLog.Calls.CACHED_NAME));

                        StatEntry StatEntry1 = null;

                        int id = cur.getInt(cur.getColumnIndex(CallLog.Calls._ID));

                        int type = cur.getInt(cur.getColumnIndex(CallLog.Calls.TYPE));

                        if (callNumber != null & duration > 0 && (type == 1 || type == 2)) {

                            int n = callNumber.length();
                            String lastDigits;
String number = callNumber.replaceAll(Pattern.quote("+"), ""); //replacing the plus
    //am just checking last 5digitis and saving to map so that we can get same //number duration
                            if (n >= 5) {

                                try {

                                    lastDigits = String.valueOf(Long.parseLong(number) % 100000);
                                } catch (NumberFormatException e) {
                                    e.printStackTrace();
                                    lastDigits = callNumber;
                                }
                            } else {
                                lastDigits = callNumber;
                            }

                            if (callLogMap1.containsKey(lastDigits)) {
                                StatEntry1 = callLogMap1.get(callNumber);

                                    StatEntry1.setTitle(callNumber);
                                StatEntry1.Duration += duration;


                            } else {
                                StatEntry1 = new StatEntry();

                  StatEntry1.setTitle(callNumber);

      StatEntry1.Duration += duration;
                           }


                    StatEntry1.setTime((StatEntry1.Duration) / 60);


                            callLogMap1.put(callNumber, StatEntry1);


                        }
                    }

                } catch (Exception e) {
                    e.printStackTrace(

                    );
                } finally {
                    cur.close();
                }
            }

atlast 将 hashmap 数据传递给 arraylist。

ArrayList<StatEntry> callLogList1 = new ArrayList<>(callLogMap1.size());

        if (callLogMap1.size() > 0) {
            for (Map.Entry<String, StatEntry> entry : callLogMap1.entrySet()) {
                callLogList1.add(entry.getValue());


            }
        }

希望这对观众有帮助。