如何返回有效的JSON对象？

Question

我刚刚进入php,我遇到了返回JSON对象的问题.

这是代码:

$stmt->bind_result($image_link, $start_time, $end_time, $viet_performer, $english_performer, $viet_event, $english_event, $day, $stage);

            while($stmt->fetch())
            {
                echo json_encode([["image_link" => $image_link,"start_time" => $start_time, "end_time" => $end_time, "viet_performer" => $viet_performer,
                                "english_performer" => $english_performer, "viet_event" => $viet_event, "english_event" => $english_event, "day" => $day,
                                "stage" => $stage]]);

                $stmt->bind_result($image_link, $start_time, $end_time, $viet_performer, $english_performer, $viet_event, $english_event, $day, $stage);
            }

这基本上输出:

{ "图片链接": "schedule_music.jpg", "START_TIME": "17:00", "END_TIME": "18:30", "viet_performer": "", "english_performer": "", "viet_event":" ","english_event":"Tet Music","day":0,"stage":1} {"image_link":"schedule_music.jpg","start_time":"11:00","end_time":"12 :00" , "viet_performer": "", "english_performer": "", "viet_event": "新罕布什尔州C", "english_event？": "音乐", "天":1, "阶段":0}

//再说一遍

但是,根据JSON验证器,它是一个无效的JSON对象.

我想生成一个有效的JSON,如下所示:

[{ "图片链接": "schedule_music.jpg", "START_TIME": "17点", "END_TIME": "18:30", "viet_performer": "", "english_performer": "", "viet_event": "","english_event":"Tet Music","day":0,"stage":1},{"image_link":"schedule_music.jpg","start_time":"11:00","end_time": "12:00", "viet_performer": "", "english_performer": "", "viet_event": "新罕布什尔C吗？", "english_event": "音乐", "天":1, "阶段":0} ]

注意开始/结束括号以及逗号分隔符.

我怎样才能做到这一点？

这是一个更好的例子(在某处找到)我的输出类似的样子:

{
    "id": "a1",
    "session": "General",
    "name": "Exhibitor Setup Begins",
    "startTime": "0900",
    "details": "9am Exhibitor Hall",
    "png": "image",
    "speaker1": "Johnson",
    "speaker2": "Nelson",
    "speaker3": ""
}{
    "id": "b1",
    "session": "General",
    "name": "Conference Registration",
    "startTime": "1000",
    "details": "10am Noon Upper Level Lobby",
    "png": "image",
    "speaker1": "Jackson",
    "speaker2": "",
    "speaker3": ""
}

我想如何让输出看起来像:

[
    {
        "id": "a1",
        "session": "General",
        "name": "Exhibitor Setup Begins",
        "startTime": "0900",
        "details": "9am Exhibitor Hall",
        "png": "image",
        "speaker1": "Johnson",
        "speaker2": "Nelson",
        "speaker3": ""
    },
    {
        "id": "b1",
        "session": "General",
        "name": "Conference Registration",
        "startTime": "1000",
        "details": "10am Noon Upper Level Lobby",
        "png": "image",
        "speaker1": "Jackson",
        "speaker2": "",
        "speaker3": ""
    }
]

Answer 1

关于更新的代码,问题是您是分别编码每个部分而不是一次编码所有数据.试试这个:

$stmt->bind_result($image_link, $start_time, $end_time, $viet_performer, $english_performer, $viet_event,
    $english_event, $day, $stage);

$data = [];
while ($stmt->fetch()) {
    $data[] = [
        "image_link"        => $image_link,
        "start_time"        => $start_time,
        "end_time"          => $end_time,
        "viet_performer"    => $viet_performer,
        "english_performer" => $english_performer,
        "viet_event"        => $viet_event,
        "english_event"     => $english_event,
        "day"               => $day,
        "stage"             => $stage
    ];
}

echo json_encode($data);

根据问题的早期版本做出回应:

看起来你想要一个对象数组:

echo json_encode([
    [
        "image_link"        => $image_link,
        "start_time"        => $start_time,
        "end_time"          => $end_time,
        "viet_performer"    => $viet_performer,
        "english_performer" => $english_performer,
        "viet_event"        => $viet_event,
        "english_event"     => $english_event,
        "day"               => $day,
        "stage"             => $stage
    ]
]);

请注意,包含字符串键的数组将转换为对象json_encode.在上面的代码中,内部数组变为对象,而外部数组则不变.

这可能是一种更直观的方式来看待它:

$objectOne = (object) [
    "image_link"        => $image_link,
    "start_time"        => $start_time,
    "end_time"          => $end_time,
    "viet_performer"    => $viet_performer,
    "english_performer" => $english_performer,
    "viet_event"        => $viet_event,
    "english_event"     => $english_event,
    "day"               => $day,
    "stage"             => $stage
];

$objectTwo = (object) [
    "image_link"        => $image_link,
    "start_time"        => $start_time,
    "end_time"          => $end_time,
    "viet_performer"    => $viet_performer,
    "english_performer" => $english_performer,
    "viet_event"        => $viet_event,
    "english_event"     => $english_event,
    "day"               => $day,
    "stage"             => $stage
];

echo json_encode([$objectOne, $objectTwo]);