请考虑以下示例:
case class Person(name: String, age: Int)
case class Family(surname: String, members: List[Person])
val families = List(
Family("Jones",
List(Person("Indiana", 50), Person("Molly", 20))),
Family("Black",
List(Person("Jack", 55), Person("Derek", 12))))
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我想编写一个函数来查找List[Family]对象中具有特定名称的人.这是我目前的解决方案:
def find(name: String, families: List[Family]): Option[Person] = {
families.find(f => f.members.exists(m => m.name == name)).map(f => f.members.find(m => m.name == name).get)
}
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是否有更高效,更优雅(和功能)的方式来实现这一目标?