Silverlight HTTP POST少数变量,SIMPLEST示例(最少代码)

Question

您好我想将一些来自silverlight的数据发布到网站上.
我找到了以下链接,它的工作原理......
但......这个例子非常详细,让我的眼睛受伤了.
另外.. flex示例更清洁/更少代码..

我会说必须有更好的解决方案......

供参考..我们发布2个变量(字符串)并读出结果(字符串).

来自链接的解决方案:

   1. // C#  
   2. // Create a request object  
   3. HttpWebRequest request = (HttpWebRequest)WebRequest.Create(new Uri(POST_ADDRESS, UriKind.Absolute));  
   4. request.Method = "POST";  
   5. // don't miss out this  
   6. request.ContentType = "application/x-www-form-urlencoded";  
   7. request.BeginGetRequestStream(new AsyncCallback(RequestReady), request);  
   8.   
   9. // Sumbit the Post Data  
  10. void RequestReady(IAsyncResult asyncResult)  
  11. {  
  12.     HttpWebRequest request = asyncResult.AsyncState as HttpWebRequest;  
  13.     Stream stream = request.EndGetRequestStream(asyncResult);  
  14.   
  15.     // Hack for solving multi-threading problem  
  16.     // I think this is a bug  
  17.     this.Dispatcher.BeginInvoke(delegate()  
  18.     {  
  19.         // Send the post variables  
  20.         StreamWriter writer = new StreamWriter(stream);  
  21.         writer.WriteLine("key1=value1");  
  22.         writer.WriteLine("key2=value2");  
  23.         writer.Flush();  
  24.         writer.Close();  
  25.   
  26.         request.BeginGetResponse(new AsyncCallback(ResponseReady), request);  
  27.     });  
  28. }  
  29.   
  30. // Get the Result  
  31. void ResponseReady(IAsyncResult asyncResult)  
  32. {  
  33.     HttpWebRequest request = asyncResult.AsyncState as HttpWebRequest;  
  34.     HttpWebResponse response = (HttpWebResponse)request.EndGetResponse(asyncResult);  
  35.   
  36.     this.Dispatcher.BeginInvoke(delegate()  
  37.     {  
  38.         Stream responseStream = response.GetResponseStream();  
  39.         StreamReader reader = new StreamReader(responseStream);  
  40.     // get the result text  
  41.         string result = reader.ReadToEnd();  
  42.     });  
  43. }  

Answer 1

您可以使用WebClient发送表单数据.如果你不关心成功的确认,那将很短:

WebClient wc = new WebClient();
wc.Headers["Content-type"] = "application/x-www-form-urlencoded";
wc.UploadStringAsync(new Uri(postUrl), "POST", "val1=param1&val2=param2");