ita*_*shi 5 java concurrency multithreading atomic synchronized
我正在尝试使用方法上的同步与原子变量(java.util.concurrent.atomic包)进行Java多线程.
以下是课程:
// Interface ICounter.java
public interface ICounter {
public void increment();
public void decrement();
public int value();
}
// Class Counter.java
public class Counter implements ICounter {
private int c = 0;
@Override
public void increment() {
c++;
}
@Override
public void decrement() {
c--;
}
@Override
public int value() {
return c;
}
}
// Class AtomicCounter.java
import java.util.concurrent.atomic.AtomicInteger;
public class AtomicCounter implements ICounter {
private AtomicInteger c = new AtomicInteger(0);
@Override
public void increment() {
c.incrementAndGet();
}
@Override
public void decrement() {
c.decrementAndGet();
}
@Override
public int value() {
return c.get();
}
public long getIncrement() {
return c.incrementAndGet();
}
}
// Class MainProg.java
public class MainProg {
public static void main(String args[]) {
ICounter counter = new AtomicCounter();
//ICounter counter = new SynchronizedCounter();
Thread thread1 = new Thread(new CountRunner(counter));
Thread thread2 = new Thread(new CountRunner(counter));
thread1.start();
thread2.start();
}
}
class CountRunner implements Runnable {
private ICounter counter;
public CountRunner(ICounter counter) {
this.counter = counter;
}
public void run() {
while (true) {
counter.increment();
System.out.println(Thread.currentThread().getName() + " count=" + counter.value());
System.out.println("-------------------");
try {
Thread.sleep(2000L);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
}
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运行Atomic或Synchronized的结果不显示变量integer是线程安全的,例如:
Thread-0 count=1
-------------------
Thread-1 count=2
-------------------
Thread-0 count=3
-------------------
Thread-1 count=4
-------------------
Thread-0 count=5
-------------------
Thread-1 count=6
-------------------
Thread-0 count=7
-------------------
Thread-1 count=8
-------------------
Thread-0 count=10
-------------------
Thread-1 count=10
-------------------
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从结果中,最后两行显示2个线程正在访问计数器类的整数变量的相同值.也许我在这里错过了一些东西?
谢谢!
您在一个步骤中递增该值,然后在另一步骤中获取该值。虽然下面的类保证每个单独的步骤都是原子的AtomicInteger,但进行两个单独的操作的事实使您在 print 语句中看到的值受到线程执行顺序的影响。
为了能够准确地显示给定线程更新的值,您需要在单个操作中更新并获取结果值,正如您的getIncrement()方法所做的那样。将为您提供预期结果的代码如下所示:
int changedValue = counter.getIncrement();
System.out.println(Thread.currentThread().getName() + " count=" + changedValue);
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