使用对象数组列表作为微调器适配器

Raf*_*ael 19 user-interface android spinner drop-down-menu

我得到了这个对象的ArrayList,我需要将它设置为我的spinner的适配器,如下所示:

ArrayList<Contact> contactlist= new ArrayList<Contact>();
contactlist.add("Gabe");
contactlist.add("Mark");
contactlist.add("Bill");
contactlist.add("Steve");

ArrayAdapter adapter = new ArrayAdapter(this, android.R.layout.simple_spinner_item, contactlist);
    adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);

contactsSpinner.setAdapter(adapter);
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这是我的Contact对象的一个​​例子,它只有两个变量,Name和ID

Contact contact = new Contact();
    contact.setName("Gabe")
    contact.setID("14575")
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我需要让微调器显示来自ArrayList的联系人姓名,因为它显示了内存中的联系地址,选中后,我需要返回联系人ID,以执行其他操作.我怎样才能做到这一点?

Pan*_*ade 70

嗨,您需要做的很容易,对您的类Contact,覆盖其中的toString()方法并返回联系人的姓名.

看一下这个例子.它也可以在github中找到

public class SpinnerTestOneActivity extends AppCompatActivity {

    private Spinner spinner;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_spinner_test_one);
        Toolbar toolbar = (Toolbar) findViewById(R.id.my_custom_toolbar);
        setSupportActionBar(toolbar);

        getSupportActionBar().setDisplayHomeAsUpEnabled(true);

        initializeUI();
    }

    private void initializeUI() {

        spinner = (Spinner) findViewById(R.id.SpinnerTestOneActivity_spinner);

        ArrayList<Contact> contacts = new ArrayList<>();

        for (int i = 0; i < 10; i++) {
            contacts.add(new Contact("Name_" + i, "Id_" + i));
        }

        ArrayAdapter<Contact> adapter =
                new ArrayAdapter<Contact>(getApplicationContext(),  android.R.layout.simple_spinner_dropdown_item, contacts);
        adapter.setDropDownViewResource( android.R.layout.simple_spinner_dropdown_item);

        spinner.setAdapter(adapter);

    }

    private class Contact {
        private String contact_name;
        private String contact_id;

        public Contact() {
        }

        public Contact(String contact_name, String contact_id) {
            this.contact_name = contact_name;
            this.contact_id = contact_id;
        }

        public String getContact_name() {
            return contact_name;
        }

        public void setContact_name(String contact_name) {
            this.contact_name = contact_name;
        }

        public String getContact_id() {
            return contact_id;
        }

        public void setContact_id(String contact_id) {
            this.contact_id = contact_id;
        }

        /**
         * Pay attention here, you have to override the toString method as the
         * ArrayAdapter will reads the toString of the given object for the name
         *
         * @return contact_name
         */
        @Override
        public String toString() {
            return contact_name;
        }
    }

}
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产量

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  • 非常坦克!+1这个很棒的答案. (2认同)
  • 哇!仅仅通过覆盖`toString()`方法就可以节省一天,谢谢! (2认同)