从资源创建 File 对象

Nee*_*eel 3 resources android uri file

我有一个位于 /res/introduced.xml 的文件。我知道我可以通过两种方式访问​​它:

1)R.引入的资源

2) 一些绝对/相对 URI

我正在尝试创建一个 File 对象,以便将它传递给特定的类。我怎么做?

Nee*_*eel 5

这就是我最终做的:

try{
  InputStream inputStream = getResources().openRawResource(R.raw.some_file);
  File tempFile = File.createTempFile("pre", "suf");
  copyFile(inputStream, new FileOutputStream(tempFile));

  // Now some_file is tempFile .. do what you like
} catch (IOException e) {
  throw new RuntimeException("Can't create temp file ", e);
}

private void copyFile(InputStream in, OutputStream out) throws IOException {
    byte[] buffer = new byte[1024];
    int read;
    while((read = in.read(buffer)) != -1){
      out.write(buffer, 0, read);
    }
}
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