Sendgrid API - 错误的用户名/密码错误

Question

我正在尝试使用Sendgrid发送我的第一封电子邮件:

$sendgrid = new SendGrid('username', 'xx.xxxxxxxxxxxxxxxx.xxxxxxxxxxxxxxxxxxxxxxx_xxxxxxxxxxxxxxxxxx');
$email = new SendGrid\Email();

$email->addTo("email1@gmail.com")
      ->setFrom("email@domain.com")
      ->setSubject("Sending with SendGrid is Fun")
      ->setHtml("and easy to do anywhere, even with PHP");

这是我遇到的错误:

PHP致命错误:未捕获的异常'SendGrid\Exception',消息为"{"errors":["Bad username/password"],"message":"error"}'

我使用来自Sendgrid设置的真实API密钥信息,而不是'username'和'xx.xxxxxxxxxxxxxxxx.xxxxxxxxxxxxxxxxxxxxxxx_xxxxxxxxxxxxxxxxxx'.

我使用了创建API密钥后提供的长字符串密钥.但是这行似乎还有问题:$ sendgrid = new SendGrid('username','xx.xxxxxxxxxxxxxxxx.xxxxxxxxxxxxxxxxxxxxxxx_xxxxxxxxxxxxxxxxxx');

我应该在哪里获取授权信息,以便我不会收到错误的用户名/密码错误？

Answer 1

另一个可能的答案是只将api键传递给SendGrid()构造函数;

$sendgrid = new SendGrid('xx.xxxxxxxxxxxxxxxx.xxxxxxxxxxxxxxxxxxxxxxx_xxxxxxxxxxxxxxxxxx');
$email = new SendGrid\Email();

$email->addTo("email1@gmail.com")
      ->setFrom("email@domain.com")
      ->setSubject("Sending with SendGrid is Fun")
      ->setHtml("and easy to do anywhere, even with PHP");