Rag*_*der 2 python arrays list
到目前为止,我在网络上还没有找到任何可以帮助解释这一问题的东西,我认为这一定对我有帮助。问题是,在使用Spyder2作为IDE的Python 3.4中,我一直在列表中遇到语法错误,我需要帮助来理解它。
所以这是我尝试过的。
当我将列表保持相对较小时,它似乎可以正常工作,但是一旦超过76个字符,就会出现此错误:
Run Code Online (Sandbox Code Playgroud)runfile('C:/Users/ghost/.spyder2-py3/temp.py', wdir='C:/Users/ghost/.spyder2-py3') File "C:/Users/ghost/.spyder2-py3/temp.py", line 7 alphabet = [a = 0, b = 1, c = 3, d = 4, e = 5, f = 6, g = 7, h = 8, SyntaxError: invalid syntax
码
# -*- coding: utf-8 -*-
"""
Spyder Editor
This is a temporary script file.
"""
alphabet = [a = 0, b = 1, c = 3, d = 4, e = 5, f = 6, g = 7, h = 8,
i = 9, j = 10, k = 11, l = 12, m = 13, n = 14, o = 15, p = 16,
q = 17, r = 18, s = 19, t = 20, u = 21, v = 22, w = 23, y = 24,
x = 25, z = 26]
print(alphabet)
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那是不正确的语法。您有[]一个list,但您要将每个值分配给另一个值,该值更像是dict,因此不起作用。您可以通过将其发送给dict()函数以创建字典,以最小的更改来解决此问题:
>>> alphabet = dict(a = 0, b = 1, c = 3, d = 4, e = 5, f = 6, g = 7, h = 8,
... i = 9, j = 10, k = 11, l = 12, m = 13, n = 14, o = 15, p = 16,
... q = 17, r = 18, s = 19, t = 20, u = 21, v = 22, w = 23, y = 24,
... x = 25, z = 26)
>>> alphabet['b']
1
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