C#Basic OOP - 使用构造函数创建类的字典

Cis*_*ega 4 c# oop dictionary class list

我一直在尝试的代码和出了什么问题:http://ideone.com/cvLRLg

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ConsoleApplication1
{
    public class Minion
    {
        public static int manaCost;
        public static int attack;
        public static int health;
        public static string cardText;
        public Minion(int mana, int atk, int h, string txt)
        {
            manaCost = mana;
            attack = atk;
            health = h;
            cardText = txt;
        }
        public void displayStats(string name)
        {
            Console.WriteLine(name + "\nMana Cost: " + manaCost + "\nAttack: " + attack + "\nHealth: " + health + "\n" + cardText + "\n");
        }
    }
    class Program
    {
        static void Main(string[] args)
        {
            List<string> indexList = new List<string>();
            Dictionary<string, Minion> minionList = new Dictionary<string, Minion>();

            //buffer so I start at 1 and not 0
            indexList.Add("MissingNo");

            //make a Wolfrider card
            indexList.Add("Wolfrider");
            Minion Wolfrider = new Minion(3, 3, 1, "Charge");
            minionList.Add(indexList[1], Wolfrider);

            //make a Goldshire Footman card
            indexList.Add("Goldshire Footman");
            Minion GoldshireFootman = new Minion(1, 1, 2, "Taunt");
            minionList.Add(indexList[2], GoldshireFootman);

            //look through all my cards
            for (int i = 1; i < indexList.Count(); i++)
                minionList[indexList[i]].displayStats(indexList[i]);
            Console.ReadLine();
        }
    }
}
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我一直在努力教自己C#,但这一直困扰着我.我想创建一个接受字符串的Dictionary然后返回一个Minion(新类).

Minion在制作时会接受四个参数,因此我必须专门用一行代码来制作一个新的Minion,然后将其添加到Dictionary中.

然而,当我经历我拥有的所有Minions时,由于某种原因,第一个让我回到OTHER Minion的属性.

Wolfrider
Mana Cost: 1
Attack: 1
Health: 2
Taunt

Goldshire Footman
Mana Cost: 1
Attack: 1
Health: 2
Taunt
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列表工作正常,因为名称是正确的......但Wolfrider具有Goldshire Footman的属性.

有没有更有效/优化的方法来做到这一点?如果没有,我做错了什么?

ken*_*n2k 6

主要问题是您的成员是static:

public static int manaCost
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所以基本上,你影响的最后一个值获胜.将它们转换为实例属性:

public int ManaCost { get; set; }
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然后摆脱indexList并直接使用你的Minion的名字作为字典键.