asyncio:loop.run_until_complete(loop.create_task(f))打印出"永远不会检索到任务异常",即使它已经被传播了

WGH*_*WGH 3 python exception coroutine python-3.x python-asyncio

由于某种原因,该程序打印以下警告:

Task exception was never retrieved
future: <Task finished coro=<coro() done, defined at /usr/lib64/python3.4/asyncio/coroutines.py:139> exception=SystemExit(2,)>
Run Code Online (Sandbox Code Playgroud)

即使异常被清楚地检索和传播,如caught SystemExit!打印到终端,并且进程状态代码变为2.

Python 2和trollius也是如此.

我错过了什么吗?

#!/usr/bin/env python3

import asyncio

@asyncio.coroutine
def comain():
    raise SystemExit(2)

def main():
    loop = asyncio.get_event_loop()
    task = loop.create_task(comain())
    try:
        loop.run_until_complete(task)
    except SystemExit:
        print("caught SystemExit!")
        raise
    finally:
        loop.close()

if __name__ == "__main__":
    main()
Run Code Online (Sandbox Code Playgroud)

Jas*_*ohi 7

SystemExit似乎是一个特例.例如,如果你举起并抓住一个Exception,你就不会看到任何错误.解决这个问题的方法似乎是使用Task.exception()以下方法手动检索异常:

import asyncio

@asyncio.coroutine
def comain():
    raise SystemExit(2)

def main():
    loop = asyncio.get_event_loop()
    task = loop.create_task(comain())
    try:
        loop.run_until_complete(task)
    except SystemExit:
        print("caught SystemExit!")
        task.exception()
        raise
    finally:
        loop.close()

if __name__ == "__main__":
    main()
Run Code Online (Sandbox Code Playgroud)

编辑

实际上,所有BaseException子类都会以这种方式运行.