ServiceWorker注册失败:DOMException:仅允许安全源(请参阅:https://goo.gl/Y0ZkNV)

Question

我编写代码来获取GCM id以发送chrome推送通知.我在下面写了代码来获取GCM id.

var ChromePushManager = function (serviceWorkerPath, callback) {
    if ('serviceWorker' in navigator) {
        navigator.serviceWorker.register(serviceWorkerPath).then(function (registration) {
            // Registration was successful 
            console.log('ServiceWorker registration successful with scope: ', registration.scope);

            registration.pushManager.subscribe({userVisibleOnly: true}).then(function (subscription) {
                console.log("subscription.subscriptionId: ", subscription.subscriptionId);
                console.log("subscription.endpoint: ", subscription.endpoint);

                // TODO: Send the subscription subscription.endpoint
                // to your server and save it to send a push message
                // at a later date
                var register = ChromePushManager.getRegistrationId(subscription);
                callback(null, register);
            });
        }).catch(function (err) {
            // registration failed :(
            console.log('ServiceWorker registration failed: ', err);
        });
    } else {
        callback('Service workers aren\'t supported in this browser.', null);
    }
};

ChromePushManager.getRegistrationId = function (pushSubscription) {
    if (pushSubscription.subscriptionId) {
        return pushSubscription.subscriptionId;
    }

    var endpoint = 'https://android.googleapis.com/gcm/send/';
    parts = pushSubscription.endpoint.split(endpoint);

    if (parts.length > 1)
    {
        console.log("RegistrationId : " + parts[1]);
        return parts[1];
    }
}

var chromePushManager = new ChromePushManager('../js/service-worker.js', function (error, registrationId) {
                    if (error !== null) {
                        console.log(error);
                    }
});

它在http:// localhost:8080中正常工作.我在服务器上传了这段代码.我试图在服务器中执行代码.我收到了错误.

ServiceWorker注册失败:DOMException:仅允许安全源(请参阅:https://goo.gl/Y0ZkNV).

我不知道这个错误说的是什么.你能解释一下这个错误意味着什么,并给我一个解决方案来解决我在服务器端的错误.

谢谢.

Answer 1

您需要在服务器上使用http s.

错误:仅允许安全的来源(请参阅:链接).

从错误链接: