使用TypeScript返回AngularJS $ q承诺

Question

我有一个服务,包含$ http我的函数返回一个延迟对象.

我的界面:

export interface MyServiceScope {
    get: ng.IPromise<{}>;
}

我的课:

export class MyService implements MyServiceScope {

    static $inject = ['$http', '$log'];

    constructor(private $http: ng.IHttpService,
                private $log: ng.ILogService,
                private $q: ng.IQService) {
        this.$http = $http;
        this.$log = $log;
        this.$q = $q;
    }

    get(): ng.IPromise<{}> {
        var self = this;
        var deferred = this.$q.defer();

        this.$http.get('http://localhost:8000/tags').then(
            function(response) {
                deferred.resolve(response.data);
            },
            function(errors) {
                self.$log.debug(errors);
                deferred.reject(errors.data);
            }
        );

        return deferred.promise;
    }
}

编译失败,出现以下错误:

myservice.ts(10,18): error TS2420: Class 'MyService' incorrectly implements interface 'MyServiceScope'.
    Types of property 'get' are incompatible.
        Type '() => IPromise<{}>' is not assignable to type 'IPromise<{}>'.
            Property 'then' is missing in type '() => IPromise<{}>'.

作为参考,这里是 DefinitelyTyped 的IPromise定义.该IQService.defer()调用返回一个IDeferred对象,然后deferred.promise返回IPromise对象.

我不确定我是否在界面中使用了错误的定义,或者没有以相同的方式返回延迟对象.任何投入将不胜感激!

Answer 1

在您的界面中,您定义了一个属性get,在服务实现中,它是一个函数get().你可能想要的是一个函数,所以界面应该是:

export interface MyServiceScope {
    get(): ng.IPromise<{}>;
}