我有以下java类
@XmlRootElement
@XmlSeeAlso(DataClass.class)
public static class EnvelopeClass<T> {
@XmlElement
public String version;
@XmlElement
public T data;
EnvelopeClass() {
}
EnvelopeClass(String version, T data) {
this.version = version;
this.data = data;
}
}
@XmlRootElement
public static class DataClass {
@XmlElement
public String name;
DataClass() {
}
DataClass(String name) {
this.name = name;
}
}
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我正在创建它的实例并将它编组到json
EnvelopeClass<DataClass> dataClassEnvelopeClass = new EnvelopeClass<DataClass>("1.0", new DataClass("myName"));
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我有下一个结果:
{"version":"1.0","data":{"@type":"dataClass","name":"myName"}}
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我不想在json "@type":"dataClass"中有类型类型信息,换句话说我想要下一个结果:
{"version":"1.0","data":{"name":"myName"}}
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当EnvelopeClass没有Generics时,我得到了这个结果.
有没有办法做到这一点?
要获得所需的行为,可以在data属性上使用@XmlAnyElement而不是@XmlElement.对于@XmlAnyElement属性,该值将对应于具有匹配的@XmlRootElement批注的类.
EnvelopeClass
import javax.xml.bind.annotation.XmlAnyElement;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlSeeAlso;
@XmlRootElement
@XmlSeeAlso(DataClass.class)
public class EnvelopeClass<T> {
@XmlElement
public String version;
@XmlAnyElement
public T data;
EnvelopeClass() {
}
EnvelopeClass(String version, T data) {
this.version = version;
this.data = data;
}
}
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数据类
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement(name="data")
public class DataClass {
@XmlElement
public String name;
DataClass() {
}
DataClass(String name) {
this.name = name;
}
}
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演示
import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;
public class Demo {
public static void main(String[] args) throws Exception {
JAXBContext jc = JAXBContext.newInstance(EnvelopeClass.class);
DataClass data = new DataClass("myName");
EnvelopeClass envelope = new EnvelopeClass<DataClass>("1.0", data);
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.marshal(envelope, System.out);
}
}
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