我正在使用Guava 18.0 RateLimiter:
public static void simpleTst() throws Exception{
RateLimiter lt = RateLimiter.create(2);
_log.info("Acquired one " + lt.tryAcquire());
_log.info("Acquired two " + lt.tryAcquire());
}
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输出是:
: 08 16:22:10 PST.INFO1*RateLimiterTst~simpleTst@37: Acquired one true
: 08 16:22:10 PST.INFO1*RateLimiterTst~simpleTst@38: Acquired two false
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指定许可证数量12:
public static void simpleTst() throws Exception{
RateLimiter lt = RateLimiter.create(2);
_log.info("Acquired one " + lt.tryAcquire(12));
_log.info("Acquired two " + lt.tryAcquire());
}
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输出是:
: 08 16:22:36 PST.INFO1*RateLimiterTst~simpleTst@37: Acquired one true
: 08 16:22:36 PST.INFO1*RateLimiterTst~simpleTst@38: Acquired two false
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为什么会这样?
预期第一个示例的行为是因为:
// we request 2 permit per seconds
RateLimiter lt = RateLimiter.create(2);
_log.info("Acquired one " + lt.tryAcquire());
// waiting 1/2 second we will be able to get the second permit
Thread.sleep(500);
_log.info("Acquired two " + lt.tryAcquire());
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输出是:
Acquired one true
Acquired two true
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来自番石榴文档:
返回的RateLimiter确保在任何给定的秒内平均不超过permitPerSecond,持续请求在每秒平滑分布.
第二个例子的行为也是预期的,因为要成功获得第二个"获取"的单一许可我们需要等待大约6秒(= 12/2)
// we request 2 permit per seconds
RateLimiter lt = RateLimiter.create(2);
// trying to acquire 12 permits
_log.info("Acquired one " + lt.tryAcquire(12));
// waiting 12 / 2 seconds in order to be able to get the second permit
Thread.sleep(6000);
_log.info("Acquired two " + lt.tryAcquire());
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输出是:
Acquired one true
Acquired two true
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尝试获取等待时间少于6秒的最后一个许可证将失败,这就是为什么lt.tryAcquire()在您的示例中返回false.
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