带别名的Hibernate查询

Question

怎么了？

session.createCriteria(Composed.class, "main")
.createAlias("main.id.branch", "b1")
.add(Restrictions.eq("b1.owner", user))
.list();

？相应的HQL工作正常

String hql = "select main from Composed as main"
        + "left join main.id.branch as b1 where b1.owner = ?";
session.createQuery(hql)
.setInteger(0, user.id().intValue())
.list();

从Criteria开始,Hibernate没有创建任何连接和使用where b1x1_.owner_id=?,但是没有b1x1_任何地方,所以它失败了"无法准备语句".

这些课程相当简单

@Entity class Composed {
    @Id ComposedId id; // also tried @EmbeddedId
    ... irrelevant stuff
}

@Embeddable class ComposedId {
    @ManyToOne(optional=false) Branch branch;
    ... irrelevant stuff
}

@Entity class Branch {
    @Id Integer id;
    @ManyToOne(optional=false) User owner;
    ... irrelevant stuff
}

@Entity class User {
    @Id Integer id;
    ... irrelevant stuff
}

更新

我终于创建了一个SSCCE并提出了一个问题.很抱歉这个令人困惑的问题,没有SSCCE,重现起来相当困难.

Answer 1

我没有尝试，但也许用左连接创建两个别名可以帮助您。我的意思是：

session.createCriteria(Composed.class, "main")
   .createAlias("main.id", "id1", JoinType.LEFT_OUTER_JOIN)
   .createAlias("id1.branch", "b1", JoinType.LEFT_OUTER_JOIN)
   .add(Restrictions.eq("b1.owner", user))

希望能帮助到你！