Jackson XML自定义字段解串器

Question

当使用Jackson进行JSON处理时,我扩展了JsonDeserializer<T>并且能够处理自定义反序列化.与杰克逊处理XML有类似的事情吗？

import java.util.List;

public class Something {

    private int iinteger;

    private String sstring;

    private List<String> sarray;

    public Something(int iinteger, String sstring, List<String> sarray) {
        this.iinteger = iinteger;
        this.sstring = sstring;
        this.sarray = sarray;
    }

    public Shit() {
    }

    public int getIinteger() {
        return iinteger;
    }

    public void setIinteger(int iinteger) {
        this.iinteger = iinteger;
    }

    public String getSstring() {
        return sstring;
    }

    public void setSstring(String sstring) {
        this.sstring = sstring;
    }

    public List<String> getSarray() {
        return sarray;
    }

    public void setSarray(List<String> dumb) {
        this.sarray = dumb;
    }
}

我想反序列化

<?xml version="1.0"?>
<Something xmlns="">
    <iinteger>23</iinteger>
    <sstring>hey</sstring>
    <sarray >abc abd abv</sarray >
</Something>

Answer 1

除了JSON之外,Jackson还对XML进行了序列化/序列化.

您需要以下依赖项:

<dependency>
    <groupId>com.fasterxml.jackson.dataformat</groupId>
    <artifactId>jackson-dataformat-xml</artifactId>
    <version>2.6.3</version>
</dependency>

除了标准的Jackson注释和可选的JAXB注释(javax.xml.bind.annotation)之外,Jackson还提供了一些特定于XML的注释.

以下面的POJO为例:

public class Simple {
    public int x = 1;
    public int y = 2;
}

您可以使用以下命令将其序列化为XML:

ObjectMapper xmlMapper = new XmlMapper();
String xml = xmlMapper.writeValueAsString(new Simple());

结果是:

<Simple>
    <x>1</x>
    <y>2</y>
</Simple>

要反序列化:

ObjectMapper xmlMapper = new XmlMapper();
Simple value = xmlMapper.readValue("<Simple><x>1</x><y>2</y></Simple>", Simple.class);