如何从Instagram API获取裁剪图像？

Question

目前我得到这个图片:

https://scontent.cdninstagram.com/hphotos-xtp1/t51.2885-15/s320x320/e35/11950569_428157634035762_1539002513_n.jpg

但我想得到这个版本的图像:

https://igcdn-photos-b-a.akamaihd.net/hphotos-ak-xfp1/t51.2885-15/e35/c238.0.603.603/11856567_458440314342209_1536381871_n.jpg

这是我构建API URL的方式:

var apiEndpoint = "https://api.instagram.com/v1";

    function composeRequestURL() {

        var url = apiEndpoint,
            params = {};

        if (settings.next_url != null) {
            return settings.next_url;
        }

        if (settings.hash != null) {
            url += "/tags/" + settings.hash + "/media/recent";
        }
        else if (settings.search != null) {
            url += "/media/search";
            params.lat = settings.search.lat;
            params.lng = settings.search.lng;
            settings.search.max_timestamp != null && (params.max_timestamp = settings.search.max_timestamp);
            settings.search.min_timestamp != null && (params.min_timestamp = settings.search.min_timestamp);
            settings.search.distance != null && (params.distance = settings.search.distance);
        }
        else if (settings.userId != null) {
            url += "/users/" + settings.userId + "/media/recent";
        }
        else if (settings.locationId != null) {
            url += "/locations/" + settings.locationId + "/media/recent";
        }
        else {
            url += "/media/popular";
        }

        settings.accessToken != null && (params.access_token = settings.accessToken);
        settings.clientId != null && (params.client_id = settings.clientId);
        settings.minId != null && (params.min_id = settings.minId);
        settings.maxId != null && (params.max_id = settings.maxId);
        settings.show != null && (params.count = settings.show);

        url += "?" + $.param(params)

        return url;
    }

是否有任何关于获得裁剪图像的建议？非常感谢.

Answer 1

是的,有建议获得裁剪的图像.

您只需要知道图像的原始宽度和高度.

您可以/cX.Y.W.H/在裁剪图像中添加网址.

例如:图像的原始大小为1080x603.因此,要在正方形中裁剪图像,我们需要获得方形1080x1080(带有空格)并将其裁剪为603x603.

答案是:W = 603,H = 603,X =(1080-603)/ 2 = 238,Y =(1080-603)/ 2 = 238.

然后添加/c238.238.603.603/到url:

https://scontent.cdninstagram.com/hphotos-xtp1/t51.2885-15/s320x320/e35/c238.238.603.603/11950569_428157634035762_1539002513_n.jpg

那个图像是320x320,所以要让我们的方块只删除一些变量,并获取url:

https://scontent.cdninstagram.com/hphotos-xtp1/c238.238.603.603/11950569_428157634035762_1539002513_n.jpg

UPD

如果您不知道real original size图像,API会返回非方形图像的大小(以激活它:管理客户端 - >编辑 - >迁移选项卡 - >检查Non square media).

例:

链接:

https://api.instagram.com/v1/tags/nonsquare/media/recent?client_id=CLIENT-ID

从回答:

...
images: {
    low_resolution: {
        url: "https://scontent.cdninstagram.com/hphotos-xpt1/t51.2885-15/e35/p320x320/10949090_860171600771180_267418389_n.jpg",
        width: 320,
        height: 400
    },
    thumbnail: {
        url: "https://scontent.cdninstagram.com/hphotos-xpt1/t51.2885-15/s150x150/e35/c0.135.1080.1080/10949090_860171600771180_267418389_n.jpg",
        width: 150,
        height: 150
    },
    standard_resolution: {
        url: "https://scontent.cdninstagram.com/hphotos-xpt1/t51.2885-15/sh0.08/e35/p640x640/10949090_860171600771180_267418389_n.jpg",
        width: 640,
        height: 800
    }
}
...

在网址中,我们添加/pWxH/以小尺寸获取图像(对于/p640x640/和真正的原始尺寸1080x1350 Instagram返回图像640x800).您可以将此值(640x800)用作原始图像以获得裁剪图像.

在这个例子中:

API网址:

https://scontent.cdninstagram.com/hphotos-xpt1/t51.2885-15/sh0.08/e35/p640x640/10949090_860171600771180_267418389_n.jpg

原始网址:

https://scontent.cdninstagram.com/hphotos-xpt1/t51.2885-15/sh0.08/e35/10949090_860171600771180_267418389_n.jpg

裁剪(640x640)网址:

https://scontent.cdninstagram.com/hphotos-xpt1/t51.2885-15/sh0.08/e35/p640x640/c0.80.640.640/10949090_860171600771180_267418389_n.jpg

裁剪(320x320来自640x640)网址:

https://scontent.cdninstagram.com/hphotos-xpt1/t51.2885-15/sh0.08/e35/p640x640/c160.240.320.320/10949090_860171600771180_267418389_n.jpg

裁剪(320x320)网址:

https://scontent.cdninstagram.com/hphotos-xpt1/t51.2885-15/sh0.08/e35/p320x320/c0.40.320.320/10949090_860171600771180_267418389_n.jpg