Rhe*_*eel 2 c++ vector object-slicing
我想在a中存储具有相同基类的多个类std::vector
.经过一些研究,我很明显我必须使用指针来防止对象切片.但是,当我创建向量时,向其添加元素并返回它,结果向量没有正确的值.
举个例子,这是我的两个类:
class Base {
public:
int var0;
}
class Derived : public Base {
public:
int var1;
}
Run Code Online (Sandbox Code Playgroud)
这是一个简单的print
功能.作为一项规则,所有实例Base
应该有var0 == 23
,和所有实例Derived
应该有var0 != 23
.
void print(Base& value) {
if (value.var0 == 23) {
std::cout << "Base: " << value.var0 << std::endl;
} else {
Derived d = (Derived&) value;
std::cout << "Derived: " << d.var0 << ", " d.var1 << std::endl;
}
}
Run Code Online (Sandbox Code Playgroud)
首先,这确实像我想要的那样:
int main() {
int num = 10;
std::vector<Base*> vec;
for (int i = 0; i < num; i++) {
if (i % 2 == 0) {
Base b;
b.var0 = 23;
vec.push_back(&b);
} else {
Derived d;
d.var0 = 17;
d.var1 = 42;
vec.push_back(&d);
}
}
// ....
for (int i = 0; i < num; i++) {
print(*vec.at(i));
}
}
Run Code Online (Sandbox Code Playgroud)
这打印:
Base: 23
Derived: 17,42
Base: 23
Derived: 17,42
Base: 23
Derived: 17,42
Base: 23
Derived: 17,42
Base: 23
Derived: 17,42
Run Code Online (Sandbox Code Playgroud)
现在,我希望这个向量由函数返回,所以我创建了一个函数:
std::vector<Base*> createVector(int num) {
std::vector<Base*> vec;
for (int i = 0; i < num; i++) {
if (i % 2 == 0) {
Base b;
b.var0 = 23;
vec.push_back(&b);
} else {
Derived d;
d.var0 = 17;
d.var1 = 42;
vec.push_back(&d);
}
}
return vec;
}
int main() {
int num = 10;
std::vector<Base*> vec = createVector(num);
// ....
for (int i = 0; i < num; i++) {
print(*vec.at(i));
}
}
Run Code Online (Sandbox Code Playgroud)
这打印:
Derived: 2293232,0
Derived: 17,42
Derived: 2293232,0
Derived: 17,42
Derived: 2293232,0
Derived: 17,42
Derived: 2293232,0
Derived: 17,42
Derived: 2293232,0
Derived: 17,42
Run Code Online (Sandbox Code Playgroud)
这不是我想要的.我希望它像其他功能一样打印.
有什么方法可以解决这个问题吗?也许任何方式可能做整个派生类的事情好一点?
您的程序行为未定义:
Base b;
b.var0 = 23;
vec.push_back(&b);
Run Code Online (Sandbox Code Playgroud)
正在推回指向b
超出范围的变量()的指针.
为什么不用一个std::vector<std::unique_ptr<Base>>
呢?对象切片不会成为问题,向量将为您管理内存.