Golang:制作切片性能

Ant*_*ton 13 go

为什么这些基准测试结果如此不同?

func Benchmark1(b *testing.B) {
    for n := 0; n < b.N; n++ {
        _ = make([]byte, 8)
    }
}

func Benchmark2(b *testing.B) {
    length := 1
    for n := 0; n < b.N; n++ {
        _ = make([]byte, 7+length)
    }
}
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基准测试结果:

Benchmark1-8                    500000000            3.37 ns/op
Benchmark2-8                    30000000            50.6 ns/op
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pet*_*rSO 12

8在编译时计算常量表达式.它make被分配在一个goroutine堆栈上(便宜).7 + length在运行时计算变量表达式.它make是在程序堆上分配的(昂贵的).如果make堆栈分配的大小太大(例如,常量(64*1024)和变量(64*1024-1)+length),则两个分配都在堆上进行,基准时间相同.

$ go tool compile -m a_test.go
a_test.go:5: Benchmark1 b does not escape
a_test.go:7: Benchmark1 make([]byte, 8) does not escape
a_test.go:14: make([]byte, 7 + length) escapes to heap
a_test.go:11: Benchmark2 b does not escape
$ 
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a_test.go:

package a

import "testing"

func Benchmark1(b *testing.B) {
    for n := 0; n < b.N; n++ {
        _ = make([]byte, 8)
    }
}

func Benchmark2(b *testing.B) {
    length := 1
    for n := 0; n < b.N; n++ {
        _ = make([]byte, 7+length)
    }
}
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去伪汇编:

$ go tool compile -S a_test.go
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Benchmark1:

"".Benchmark1 t=1 size=112 value=0 args=0x8 locals=0x20
    0x0000 00000 (a_test.go:5)  TEXT    "".Benchmark1(SB), $32-8
    0x0000 00000 (a_test.go:5)  SUBQ    $32, SP
    0x0004 00004 (a_test.go:5)  MOVQ    "".b+40(FP), CX
    0x0009 00009 (a_test.go:5)  FUNCDATA    $0, gclocals·87d20ce1b58390b294df80b886db78bf(SB)
    0x0009 00009 (a_test.go:5)  FUNCDATA    $1, gclocals·790e5cc5051fc0affc980ade09e929ec(SB)
    0x0009 00009 (a_test.go:6)  MOVQ    $0, AX
    0x000b 00011 (a_test.go:6)  NOP
    0x000b 00011 (a_test.go:6)  MOVQ    112(CX), BX
    0x000f 00015 (a_test.go:6)  CMPQ    BX, AX
    0x0012 00018 (a_test.go:6)  JLE $0, 98
    0x0014 00020 (a_test.go:7)  MOVQ    $0, BX
    0x0016 00022 (a_test.go:7)  MOVB    BL, "".autotmp_0001(SP)
    0x0019 00025 (a_test.go:7)  MOVB    BL, "".autotmp_0001+1(SP)
    0x001d 00029 (a_test.go:7)  MOVB    BL, "".autotmp_0001+2(SP)
    0x0021 00033 (a_test.go:7)  MOVB    BL, "".autotmp_0001+3(SP)
    0x0025 00037 (a_test.go:7)  MOVB    BL, "".autotmp_0001+4(SP)
    0x0029 00041 (a_test.go:7)  MOVB    BL, "".autotmp_0001+5(SP)
    0x002d 00045 (a_test.go:7)  MOVB    BL, "".autotmp_0001+6(SP)
    0x0031 00049 (a_test.go:7)  MOVB    BL, "".autotmp_0001+7(SP)
    0x0035 00053 (a_test.go:7)  LEAQ    "".autotmp_0001(SP), BX
    0x0039 00057 (a_test.go:7)  CMPQ    BX, $0
    0x003d 00061 (a_test.go:7)  JEQ $1, 103
    0x003f 00063 (a_test.go:7)  MOVQ    $8, "".autotmp_0002+16(SP)
    0x0048 00072 (a_test.go:7)  MOVQ    $8, "".autotmp_0002+24(SP)
    0x0051 00081 (a_test.go:7)  MOVQ    BX, "".autotmp_0002+8(SP)
    0x0056 00086 (a_test.go:6)  INCQ    AX
    0x0059 00089 (a_test.go:6)  NOP
    0x0059 00089 (a_test.go:6)  MOVQ    112(CX), BX
    0x005d 00093 (a_test.go:6)  CMPQ    BX, AX
    0x0060 00096 (a_test.go:6)  JGT $0, 20
    0x0062 00098 (a_test.go:9)  ADDQ    $32, SP
    0x0066 00102 (a_test.go:9)  RET
    0x0067 00103 (a_test.go:7)  MOVL    AX, (BX)
    0x0069 00105 (a_test.go:7)  JMP 63
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Benchmark2:

"".Benchmark2 t=1 size=144 value=0 args=0x8 locals=0x58
    0x0000 00000 (a_test.go:11) TEXT    "".Benchmark2(SB), $88-8
    0x0000 00000 (a_test.go:11) MOVQ    (TLS), CX
    0x0009 00009 (a_test.go:11) CMPQ    SP, 16(CX)
    0x000d 00013 (a_test.go:11) JLS 129
    0x000f 00015 (a_test.go:11) SUBQ    $88, SP
    0x0013 00019 (a_test.go:11) FUNCDATA    $0, gclocals·87d20ce1b58390b294df80b886db78bf(SB)
    0x0013 00019 (a_test.go:11) FUNCDATA    $1, gclocals·790e5cc5051fc0affc980ade09e929ec(SB)
    0x0013 00019 (a_test.go:12) MOVQ    $1, "".length+56(SP)
    0x001c 00028 (a_test.go:13) MOVQ    $0, AX
    0x001e 00030 (a_test.go:13) MOVQ    "".b+96(FP), BP
    0x0023 00035 (a_test.go:13) NOP
    0x0023 00035 (a_test.go:13) MOVQ    112(BP), BX
    0x0027 00039 (a_test.go:13) MOVQ    AX, "".n+48(SP)
    0x002c 00044 (a_test.go:13) CMPQ    BX, AX
    0x002f 00047 (a_test.go:13) JLE $0, 124
    0x0031 00049 (a_test.go:14) MOVQ    "".length+56(SP), AX
    0x0036 00054 (a_test.go:14) ADDQ    $7, AX
    0x003a 00058 (a_test.go:14) LEAQ    type.[]uint8(SB), BX
    0x0041 00065 (a_test.go:14) MOVQ    BX, (SP)
    0x0045 00069 (a_test.go:14) MOVQ    AX, 8(SP)
    0x004a 00074 (a_test.go:14) MOVQ    AX, 16(SP)
    0x004f 00079 (a_test.go:14) PCDATA  $0, $0
    0x004f 00079 (a_test.go:14) CALL    runtime.makeslice(SB)
    0x0054 00084 (a_test.go:14) MOVQ    24(SP), BX
    0x0059 00089 (a_test.go:14) MOVQ    BX, "".autotmp_0005+64(SP)
    0x005e 00094 (a_test.go:14) MOVQ    32(SP), BX
    0x0063 00099 (a_test.go:14) MOVQ    BX, "".autotmp_0005+72(SP)
    0x0068 00104 (a_test.go:14) MOVQ    40(SP), BX
    0x006d 00109 (a_test.go:14) MOVQ    BX, "".autotmp_0005+80(SP)
    0x0072 00114 (a_test.go:13) MOVQ    "".n+48(SP), AX
    0x0077 00119 (a_test.go:13) INCQ    AX
    0x007a 00122 (a_test.go:13) NOP
    0x007a 00122 (a_test.go:13) JMP 30
    0x007c 00124 (a_test.go:16) ADDQ    $88, SP
    0x0080 00128 (a_test.go:16) RET
    0x0081 00129 (a_test.go:11) CALL    runtime.morestack_noctxt(SB)
    0x0086 00134 (a_test.go:11) JMP 0
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  • 你知道为什么在第二种情况下编译器不会在'7 + length`上执行常量传播并生成相同的代码吗?这只是Go(目前)做的事情,还是无法完成的事情? (2认同)
  • @matt:由于`7 + length`的值是一个运行时变量表达式,编译器必须进行数据流分析,以证明它对`make([],7 + length`的唯一值是8.我们写`const length = 1`这很容易.如果我们编写,就像这里的情况那样,`var length = 1`它更难和耗时.第一步是SSA编译器:[静态单一赋值形式](https: //en.wikipedia.org/wiki/Static_single_assignment_form).既然`gc`编译器是用Go编写的,那么Go的SSA`gc`编译器正在开发中:[dev.ssa](https://go.googlesource .COM /去/ +/dev.ssa). (2认同)